Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 8)
8.
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Answer: Option
Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
| Saving % = |  |
0.59x | x 100 |  % |
= 30% (approx.) |
| 2x |
Discussion:
38 comments Page 2 of 4.
King cobra said:
1 decade ago
Hey KB3. You are wrong. Solve by PYTHOGORUS theorem,,
From the fig shown above.
Root of AB square + BC square = AC.
From the fig shown above.
Root of AB square + BC square = AC.
Scott said:
1 decade ago
From the fig shown above.
Root of AB square + BC square = AC.
Root of AB square + BC square = AC.
Ajay said:
1 decade ago
Lets say sides of square is 10 and let diagonal be x therefore by Pythagoras theorem.
X2 = (10) 2 + (10) 2 = 200.
X = 10root2 = 10 x 14.1 (root2 = 1.412).
Therefore 20 - 14.1 = 5.9.
5.9/20 = 0.30 i.e. approx 30%.
X2 = (10) 2 + (10) 2 = 200.
X = 10root2 = 10 x 14.1 (root2 = 1.412).
Therefore 20 - 14.1 = 5.9.
5.9/20 = 0.30 i.e. approx 30%.
Arpit jain said:
1 decade ago
Hey kb3 u have used wrong formula
its (square root of 2)*(X)
ab+bc = 16m
sqrt(2)*8 = 11.313
16-11.313 = 4.68
(4.68*100)/16 = 29.28%
its (square root of 2)*(X)
ab+bc = 16m
sqrt(2)*8 = 11.313
16-11.313 = 4.68
(4.68*100)/16 = 29.28%
Sudhakar said:
1 decade ago
Suppose ab = 2, ac = 2 then ab+ac=4.
Diagonal bc = ?
Pythagoras Proof bc^2 = ac^2+ab^2 (here ^2 means square).
bc^2= 4+4.
bc=(square root of 8).
bc= 2.83.
Gain = 4-2.83 = 1.17.
Gain(%) = (1.17/4)*100 = 29.28%.
Diagonal bc = ?
Pythagoras Proof bc^2 = ac^2+ab^2 (here ^2 means square).
bc^2= 4+4.
bc=(square root of 8).
bc= 2.83.
Gain = 4-2.83 = 1.17.
Gain(%) = (1.17/4)*100 = 29.28%.
Atul jain said:
1 decade ago
Let we have a square. starting from left top to right A,B,C,D.
After that make a diagonal AC.
As we know that we don't know the side of square then we assume x.
Now we start to run from A to C then path is AB+BC and its value,
is x+x = 2x.
Then equation is AB+BC = 2x.
Now the diagonal of the square formula is,
d = square root of 2 x.
d = 1.41x.
Saving per cent is ((2x-1.41x)/2x)*100 .
29.5. approx 30.
After that make a diagonal AC.
As we know that we don't know the side of square then we assume x.
Now we start to run from A to C then path is AB+BC and its value,
is x+x = 2x.
Then equation is AB+BC = 2x.
Now the diagonal of the square formula is,
d = square root of 2 x.
d = 1.41x.
Saving per cent is ((2x-1.41x)/2x)*100 .
29.5. approx 30.
(1)
Suraj said:
1 decade ago
How the each side of square is 1m?
Lakshya said:
1 decade ago
Why should we have to multiply 0.59x/2x by 100? somebody please help me.
Anu said:
1 decade ago
What is that 1.41?
Pragnya said:
1 decade ago
Please can anyone explain the last step in the solution? Which formula has been used there?
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