Aptitude - Time and Distance - Discussion

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"Hold a true friend with both hands."

- (Proverb)

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

[A].	50 km	[B].	56 km
[C].	70 km	[D].	80 km

Answer: Option B

Explanation:

Let the actual distance travelled be x km.

Then, x = x + 20

10 14

14x = 10x + 200

4x = 200

x = 50 km.

Raghavendra said: (Wed, Aug 4, 2010 06:01:54 AM)

I'm not clear with the answer. Why did you take the time same in both the cases?

Gowtham said: (Wed, Aug 25, 2010 01:15:04 AM)

For the same interval if the person travelled in 14 kmph so only. or else you could solve like this 1st hour 10 =14 2nd hour 20 =28 3rd hour 30 =42 4th hour 40 =56 5th hour 50 =70 At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km. So 70 - 50 = 20. I think u got it.

Satish said: (Tue, Aug 31, 2010 02:30:03 AM)

Please give express that how to make this equation ?

Nitesh said: (Sat, Oct 9, 2010 05:52:22 AM)

@Gowtham But it is not written that time instance is same.

Savitha said: (Mon, Oct 18, 2010 02:21:57 PM)

I am not clear with the explanation and I didn't understand this step x/10=x+20/14.

Kinnari said: (Tue, Oct 19, 2010 07:05:16 AM)

It goes by the formula S=D/T (Speed = Distance/Time) So, T = D/S => T=x/10 ............(1) T = x+20/14 .........(2) Taking both the times together we get frm (1) and (2) x/10=x+20/14 Now solve it as shown above. Hope you get it now.

Krishna said: (Fri, Dec 17, 2010 06:07:39 AM)

I agree with gautam .... the time is not constant in both cases. So it is false ..... how to equate them He travels at 10km/hr and walks d km in t1 hrs Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs How can u equate t1 and t2? It is not given.

Muneer said: (Fri, Dec 24, 2010 06:08:14 AM)

Let distance travelled be x, Since the time taken is same here so, time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph (x+20)/14=x/10 5x+100=7x 2x=100 x=50

Xyz said: (Fri, Dec 31, 2010 04:12:46 AM)

Why did you take time same in both the cases?

Santosh said: (Sun, Feb 13, 2011 08:23:49 AM)

I got you Gowtham you expressed very clearly thnks 4 your expalnation.

Ilesh said: (Sun, May 22, 2011 09:33:27 AM)

Just think more here extra 4km/h speed made him to cover extra 20km right, den 4km/h is........20km(it clearly tells 1km/h is..5km) 10km/h is.......?(10*5=50km)

Kiran said: (Fri, Jun 17, 2011 01:04:52 AM)

Time = Distance / Speed Let Distance = x First Case : Person's usual speed is 10km/hr So, T = D/S and putting the values in formula we get : T = x/10 Second case : if he travels at the speed of 14km/hr then he would have walked 20 km more. We have already assumed distance as x and now in second case we have 20 km more So: T=D/S, x+20/14 So, we have: x/10 = x+20/14 And solving the above ,we get 14x = 10x+200 14x - 10x = 200 4x = 200 x = 50Km

Krishna Reddy.Gongati said: (Thu, Jul 7, 2011 08:34:47 AM)

I am not clear with the explanation and I didn't understand this step x/10=x+20/14.

Anu said: (Fri, Aug 12, 2011 05:45:35 AM)

How we get the 200 here? In this answer please help me in this case.

Selvam said: (Mon, Aug 29, 2011 12:31:32 PM)

Hey anu see cross multiplication So, x/10=(x+20)/14 first multiply the (x+20) by 10 and u ill get 10x+200 second multiply the x by 14 so u ill get 14x now 14x=10x+200 14x-10x=200 4x=200 x=200/4 x=50 I hope you will understand this.

Harpreet Kaur said: (Wed, Sep 14, 2011 10:45:39 AM)

I liked the explanation given by Kinnari. I thank you for that.

Lak Verma said: (Mon, Oct 10, 2011 03:55:34 PM)

Time not given in question so let it (X) then Speedtime=distance 14x -10x=20 X=5 hr So 105=50km question asking for distance

Rahul said: (Tue, Oct 18, 2011 09:16:21 PM)

The question is asked to find out the distance traveled by the person, and its clearly written he traveled 20km more so we equate it as (x+20) as the distance traveled by him and then when we get the value of X to be 50km. Why it is not added by 20km to get final answer as 70km ?

Jayaraj said: (Thu, Nov 24, 2011 01:34:27 PM)

Kinnari's explanation is simple and good.

Thirumoorthy Lalapet Karur(Dt) said: (Fri, Dec 30, 2011 05:44:05 PM)

Note: That in both speed Time will be same so for speed 10km/hr speed=distance/time 10 =x/time1 for speed 14km/hr 14 =(x+20)/time2 : Note time will be same so we equate these two equations respect with time time1 = time2 time1 = x/10 time2 = (x+20)/14 (X/10)=(X+20)/14 we solve this to obation right answer