In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
So we calculate the runs in the first 10 overs
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
Abc said:
(Fri, Sep 10, 2010 06:39:13 AM)
Thanks muhundhan thats great.
Swetha said:
(Thu, Dec 2, 2010 03:10:58 AM)
Why are you minus that 282 runs?
Tarun said:
(Mon, Dec 13, 2010 09:10:35 AM)
282 are not minus,here ((3.2(current run rate)*10(overs))=32runs)
are subtracted from total required runs,so 282-32=250 are the runs required in other 40 overs,
so required run rate=
250/40=6.25 runs per over.
Avinsh said:
(Tue, Dec 28, 2010 03:42:28 AM)
How to solve given problem:.
Rajana traveled a journey of 500km with speed of 50km/hr for 5 liter and traveled withe speed of 60km/hr for 5hr and then is last 5hr covers a distance of 700km and after taking rest of 3 hr again traveled. For 2 hr by covering a distance 120km find average of speed.
Nikhil said:
(Thu, Jan 6, 2011 04:39:19 AM)
Why you write 283- (3. 2*10)?
Deepa said:
(Thu, Jan 13, 2011 02:31:30 PM)
@nikhil
First we have to find no of runs scored in first 10 overs, to calculate runs scored in 10 overs we have to do 3.2*10 (means runsscored=runrate*no of overs).we get 32runs which means they have scored 32 runs in first 10 overs. so 283-32=250 runs should be scored in next 40 overs.to find the runrate, runrate=250/40 (we have to divide no of required runs by no of overs left)
Swathy said:
(Thu, Jan 20, 2011 07:30:23 AM)
Excellent deepa and muhunthan.
Srinivas Reddy said:
(Thu, Feb 3, 2011 07:05:06 AM)
First we calculate the total runs done in 10 overs by using run rate ie 10*3.2 (runs per over) = 32.
Remaining runs is 283-32 = 250.
The run rate required to achieve the target is 250 (required runs to do) /40 (remaining overs).
Gdged said:
(Tue, Feb 15, 2011 11:52:26 AM)
Why we are using this formula?
Vinoth M said:
(Thu, Feb 17, 2011 06:59:31 AM)
Formula is, average=sum of runs in each overs(s)/number of overs(n)
given n=10,average=3.2
Then,substitute values in formula,
->3.2=s/10
->s=32
in 10 overs total run is 32
target=282
Then in 40 overs thy need 250 runs
here n=40,s=250
percentage=s/n=250/40=6.25
So ans=6.25
Kalaivani said:
(Mon, Apr 25, 2011 02:35:20 PM)
Why you write 283- (3. 2*10)?
Sathi said:
(Fri, Jul 1, 2011 09:52:10 PM)
@kalaivani,
We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.
283 is total score req for 40 overs,10*3.2=32 runs scored in the first over
Nayan Das said:
(Sat, Jul 2, 2011 02:42:08 PM)
Very good explanation vinoth m, thanks.
Tanvir said:
(Sat, Jul 16, 2011 08:01:35 AM)
It may be like this:
Let the required run rate be x.
Then Run in 40 overs = 40x (Becoz run rate = run per over)
Run in 10 overs= 10x3.2 (It is given that run rate of 10 overs is 3.2)
We know we required to calculate the run rate for 282 runs.
Then according to question:
3.2x10+40x=282
32+40x=282
40x=250
x=250/40=6.25 ans
Isha Panchal said:
(Sat, Aug 20, 2011 01:17:05 PM)
