Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
Required run rate = | ![]() |
282 - (3.2 x 10) | ![]() |
= | 250 | = 6.25 |
40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
135 comments Page 1 of 14.
PRASHANTH J said:
4 weeks ago
@All.
For simple understanding.
Total Runs at the end = 282 Runs
Run Rate of 1st 10 overs = 3.2
Total Runs score in 1st 10 overs = 10*3.2 = 32Runs.
The question is what should be the Run Rate of the next 40 overs to get 282 Runs at the end of innings?
Let the Run Rate of 40overs be x
Total runs scored in 40 overs = 40*x = 40x.
We know that Total runs= Runs in 1st 10overs+runs in next 40 overs
i.e : 282 = 32 + 40x.
282-32= 40x,
250 = 40x,
x = 250/40,
x = 6.25.
Hence And 6.25 Run Rate is the right answer.
For cross-checking
282 = 32 + (40*6.25),
282 = 32 + 250,
282 = 282.
For simple understanding.
Total Runs at the end = 282 Runs
Run Rate of 1st 10 overs = 3.2
Total Runs score in 1st 10 overs = 10*3.2 = 32Runs.
The question is what should be the Run Rate of the next 40 overs to get 282 Runs at the end of innings?
Let the Run Rate of 40overs be x
Total runs scored in 40 overs = 40*x = 40x.
We know that Total runs= Runs in 1st 10overs+runs in next 40 overs
i.e : 282 = 32 + 40x.
282-32= 40x,
250 = 40x,
x = 250/40,
x = 6.25.
Hence And 6.25 Run Rate is the right answer.
For cross-checking
282 = 32 + (40*6.25),
282 = 32 + 250,
282 = 282.
(2)
Bhavik said:
2 months ago
10 overs -> 3.2 RR ==> so we get 32runs in 10overs.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.
(9)
Arunpandiyan said:
4 months ago
In the first 10 overs, we got a total runs is 10 * 3.2 = 32
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
(14)
Srijan said:
10 months ago
I understand the solution with the help of the given explanation. Thanks, everyone.
(25)
Karthi said:
11 months ago
First 10 - run rate 3.2
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
(45)
Cherry aishu said:
1 year ago
Avg of 6 months = (6435+6927+6855+7230+6562+x)/6 = 6500.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(6)
Kondru Durga Srinu said:
1 year ago
Runs scored= overs * runrate.
= 10 *3.2.
Runs scored in 10 overs is 32 runs.
Total runs for 50 overs= 282runs.
Runs for 40 overs is = 282-32.
= 250 runs.
Runrate for 40 overs is = 250/40 is 6.25 (option A).
= 10 *3.2.
Runs scored in 10 overs is 32 runs.
Total runs for 50 overs= 282runs.
Runs for 40 overs is = 282-32.
= 250 runs.
Runrate for 40 overs is = 250/40 is 6.25 (option A).
(69)
Kondru Durga Srinu said:
1 year ago
So we calculate the runs in the first 10 overs = 10 * 3.2
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
(11)
Bhukya Praveen said:
1 year ago
10 overs ------------ 3.2 rr
40 overs ------------ ?
Target = 282.
First 10 overs => 10 x 3.2 = 32 Runs.
282 - 32 = 250 Runs Scored in the remaining 40 overs.
Total 50 overs
RunRate in remaining 40 overs => 250/40.
=> 6.25 RR.
40 overs ------------ ?
Target = 282.
First 10 overs => 10 x 3.2 = 32 Runs.
282 - 32 = 250 Runs Scored in the remaining 40 overs.
Total 50 overs
RunRate in remaining 40 overs => 250/40.
=> 6.25 RR.
(31)
Shreya Dakhale said:
2 years ago
Total Runs in 10 overs/number of overs = run rate.
Total Runs in 10 overs/10 = 3.2.
Total Runs in 10 overs = 32.
Scores to achieve - Total Runs in 10 overs.
282 - 32 = 250.
250/40 = run rate.
So, run rate = 6.25.
Total Runs in 10 overs/10 = 3.2.
Total Runs in 10 overs = 32.
Scores to achieve - Total Runs in 10 overs.
282 - 32 = 250.
250/40 = run rate.
So, run rate = 6.25.
(47)
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