Verbal Reasoning - Direction Sense Test - Discussion
Discussion Forum : Direction Sense Test - Direction Sense 1 (Q.No. 7)
7.
Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?
Answer: Option
Explanation:
Discussion:
42 comments Page 1 of 5.
Amruta said:
1 decade ago
Can anyone tell how 150 comes ?
Pravallika said:
1 decade ago
150 is used because it is mentioned that the cars are 150 km apart.
Chandan said:
1 decade ago
As soon 1st car has started moving, it leaves the main road.After running 25 km+ 15 km+ 25 km it takes the direction to back to main road that means it has to travel 15 km to reach main road.
So distance b/w 1st and 2nd car should be,
= 150+15-(25+25+35).
= 165-85 = 80.
So distance b/w 1st and 2nd car should be,
= 150+15-(25+25+35).
= 165-85 = 80.
Sravya said:
1 decade ago
Now A travels total 50km. Because he travels extra 15 km to reach the main road. It is additional to reach the main road. He travels directly another 25 km.
So 15 km is not considered.
So 15 km is not considered.
Kakoli said:
1 decade ago
@Sravya.
15 km is an unnecessary data here. Do it as simply as possible.
At the starting point distance between them is 150 km. While the first car passed 5o km at the same time second car passed 35 km. Now, distance between them {150- (50+35) }= 65.
Hope you get it.
Thanks.
15 km is an unnecessary data here. Do it as simply as possible.
At the starting point distance between them is 150 km. While the first car passed 5o km at the same time second car passed 35 km. Now, distance between them {150- (50+35) }= 65.
Hope you get it.
Thanks.
Nitika Kapoor said:
1 decade ago
It is clearly mentioned in the question that the car after travelling goes BACK to the main road! Then how can we do (25+25+35).
Since it is given that the total distance is 150 km between the two cars at starting position, and that the other car has travelled 35 km ON THE MAIN ROAD, then how can we make FE with CD, it should be made with AB (the path of the first car on the main road).
Therefore, it will be:
150-(AB+FE).
= 150-(25+35).
= 150-60.
= 90.
Since it is given that the total distance is 150 km between the two cars at starting position, and that the other car has travelled 35 km ON THE MAIN ROAD, then how can we make FE with CD, it should be made with AB (the path of the first car on the main road).
Therefore, it will be:
150-(AB+FE).
= 150-(25+35).
= 150-60.
= 90.
Neha said:
1 decade ago
Why 15 is not added?
Surya said:
1 decade ago
Can anybody give detailed answer step by step?
Ratnesh pareek said:
1 decade ago
Why 15 is not added? Can anyone explain please?
Vinitha said:
10 years ago
Can any one explain why 15 km is not taken for consideration?
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