Verbal Reasoning - Direction Sense Test - Discussion
Discussion Forum : Direction Sense Test - Direction Sense 1 (Q.No. 7)
7.
Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?
Answer: Option
Explanation:

Discussion:
42 comments Page 1 of 5.
Prajwal Surendra Naik said:
5 months ago
The answer will be correct when we assume for example in the direction max the shortest distance we prefer.
Here when he takes the final 25 km left turn .To reach the main road he might prefer a 15km left turn to reach the main road so that he is covering the main road distance of 50km.
But my question is why this kind of assumption may lead to different answers and that one will be correct according to everyone's assumptions right.
Anyone, please clarify my doubt.
Here when he takes the final 25 km left turn .To reach the main road he might prefer a 15km left turn to reach the main road so that he is covering the main road distance of 50km.
But my question is why this kind of assumption may lead to different answers and that one will be correct according to everyone's assumptions right.
Anyone, please clarify my doubt.
(1)
Sue M said:
8 years ago
I think that the main confusion is about how to interpret " take the direction to reach the main road". if condition allows, the 1st car is going to turn left and reach the main road (that is what the question is looking for).
Thus, when the 1st car reaches the main road, it has moved on the main road direction 25+25=50 km towards the other car. The other car moved 35km closer, i.e. the they are 85 km closer than when they first started from. 150-85=65km
Thus, when the 1st car reaches the main road, it has moved on the main road direction 25+25=50 km towards the other car. The other car moved 35km closer, i.e. the they are 85 km closer than when they first started from. 150-85=65km
Nitika Kapoor said:
1 decade ago
It is clearly mentioned in the question that the car after travelling goes BACK to the main road! Then how can we do (25+25+35).
Since it is given that the total distance is 150 km between the two cars at starting position, and that the other car has travelled 35 km ON THE MAIN ROAD, then how can we make FE with CD, it should be made with AB (the path of the first car on the main road).
Therefore, it will be:
150-(AB+FE).
= 150-(25+35).
= 150-60.
= 90.
Since it is given that the total distance is 150 km between the two cars at starting position, and that the other car has travelled 35 km ON THE MAIN ROAD, then how can we make FE with CD, it should be made with AB (the path of the first car on the main road).
Therefore, it will be:
150-(AB+FE).
= 150-(25+35).
= 150-60.
= 90.
Ganesh mhaske said:
6 years ago
As clearly mentioned in the question.
After 25km first car takes right and travels 15 km and then it travels to left 15 km, now in question they said that car takes back to reach the main road means car reaches to the same point where it had taken 1st turn so total distance travelled by car on the main road is still 25 km and 2nd car is 35 km so from this explanation answer is 90km is the distance between two cars.
After 25km first car takes right and travels 15 km and then it travels to left 15 km, now in question they said that car takes back to reach the main road means car reaches to the same point where it had taken 1st turn so total distance travelled by car on the main road is still 25 km and 2nd car is 35 km so from this explanation answer is 90km is the distance between two cars.
(5)
Aditya said:
10 years ago
It's simple,
Both of them being on the opposite side of a main road (facing each other) 150 km apart.
One of them moves 25km, then diverts for 15 km (no need for calculation) and then moves 25 km and then back to main road, whereas the other person moves 35km from opposite side.
So the distance travelled by one is 25 + 25 = 50 km and the other is 35 km. Distance between them currently is 150 - (50 + 35) = 65km.
Both of them being on the opposite side of a main road (facing each other) 150 km apart.
One of them moves 25km, then diverts for 15 km (no need for calculation) and then moves 25 km and then back to main road, whereas the other person moves 35km from opposite side.
So the distance travelled by one is 25 + 25 = 50 km and the other is 35 km. Distance between them currently is 150 - (50 + 35) = 65km.
Shreya said:
9 years ago
It means the first car reaches to the main road, at this point, if calculate how much first car travelled exactly on main road i.e. Horizontal distance at the main road, it will be 25 + 25 = 50m. Since total distance = 150.
The first car travelled 50. The 2nd car travelled 35. Remaining distance. = distance b/w both car at main road = 150 - (50 + 35) = 65.
The first car travelled 50. The 2nd car travelled 35. Remaining distance. = distance b/w both car at main road = 150 - (50 + 35) = 65.
Muskan said:
7 years ago
I want to ask that in this question both the car start at the same time right?
But after that it says that first car run 25 km and then take right with 15 km and then turn left
Here the distance travelled by 1st car is 25+15+25=65.
And 2nd car travel 35 km.
So 150-[65+35]=50 .
It should be like this right?
Please clear me.
But after that it says that first car run 25 km and then take right with 15 km and then turn left
Here the distance travelled by 1st car is 25+15+25=65.
And 2nd car travel 35 km.
So 150-[65+35]=50 .
It should be like this right?
Please clear me.
Chandra Sekhar said:
7 years ago
@All.
In the question, it is said that two cars on the main road. That means the second is still on the main road whereas the first car travelled a right side of the main for 15 km. It formed the right-angled triangle. For the two cars present positions, then the options given are not correct.
Please clarify my doubt
In the question, it is said that two cars on the main road. That means the second is still on the main road whereas the first car travelled a right side of the main for 15 km. It formed the right-angled triangle. For the two cars present positions, then the options given are not correct.
Please clarify my doubt
Rajneet Kaur said:
6 years ago
As per my understanding, the distance 150 km given between the two cars is on the main road(horizontally shown in the diagram), it does not include other roads it took turns to, so we'll not add the distance travelled by the first car to go back to the main road. So simply it will be 150 - (25 + 25 + 35) = 65.
(1)
Aanie said:
8 years ago
I think the given answer figure is confusing.
Redraw the figure as. Car A first moved 25 km along the main road then took a right turn and moved 15 km and so.
Now if A takes the direction back (ie: moved towards the main road) we the distance 50 Km.
Now, 150- (50+35) =65.
Am I right?
Redraw the figure as. Car A first moved 25 km along the main road then took a right turn and moved 15 km and so.
Now if A takes the direction back (ie: moved towards the main road) we the distance 50 Km.
Now, 150- (50+35) =65.
Am I right?
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