### Discussion :: Arithmetic Reasoning - Section 1 (Q.No.24)

Mounika said: (May 25, 2011) | |

Here 4m 1 to 10 , we clearly have 10 no's:3,13,23,33,43,53,63,73,83,93 and more 9 no's:30,31,32,34,35,36,37,38,39 Since we have calculated 33 already need not count here . Hence answer is 19. |

Senthilkumar said: (Jun 18, 2011) | |

NO the answer was 20 because in 33 we wrote down 3 in two times so 20 is the right answer but here they mistakenly said 33 two times |

Ashish said: (Aug 10, 2011) | |

Yes the answer should be 19. |

Sundar said: (Aug 11, 2011) | |

@All The correct answer is 20. 03, 13, 23, 43, 53, 63, 73, 83, 93 = 9 3s are there 30, 31, 32, 34, 35, 36, 37, 38, 39 = 9 3s are there 33 = 2 3s are there Total = 9 + 9 + 2 = 20. |

Paulwin Jerome said: (Feb 2, 2015) | |

3, 13, 23, 33, 43, 53, 63, 73, 83, 93 = Eleven 3's. 30, 31, 32, 34, 35, 36, 37, 38, 39 = Nine 3's. Therefor 11 + 9 = 20. |

Almojeed said: (Nov 19, 2016) | |

It's wrong, because 33 was counted twice. Therefore, the answer is 19. |

Shravan Sharma said: (Feb 7, 2017) | |

The correct answer is 19. 10 times from 30 to 39 and rest 9 from 3, 13, 23, 43, 53, 63, 73, 83, 93. |

Lokesh Sanam said: (May 8, 2017) | |

Why to count 33 two times? Please explain it. |

Siyad said: (Jun 13, 2017) | |

@Mounika @Ashish @Almojeed @Shravan Sharma @Lokesh Sanam. The answer is Option [C]. 20. In 33, we have to write 3 twice. Hope you will understand. |

Mark John Ureta said: (Feb 12, 2018) | |

Treat 3 as ones digit different to 3 use as a tens digit. |

Vishwajeet said: (Feb 27, 2018) | |

33 is counted double. Answer should be 19. |

Himanshu Kumar Tiwari said: (Aug 25, 2018) | |

The Right answer is 19. |

Nisha Pawar said: (Sep 1, 2018) | |

The Right answer is 20. I agree. |

Digvijay said: (Dec 22, 2018) | |

@Sundar you're right. In 33 we write 3 two times. |

Pankaj said: (Jan 5, 2019) | |

20 because 33 has 2 3's. |

Neeraja said: (Jul 14, 2020) | |

Thanks @Sundar. |

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