Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 24)
24.
If you write down all the numbers from 1 to 100, then how many times do you write 3 ?
Answer: Option
Explanation:
Clearly, from 1 to 100, there are ten numbers with 3 as the unit's digit- 3, 13, 23, 33, 43, 53, 63, 73, 83, 93; and ten numbers with 3 as the ten's digit - 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.
So, required number = 10 + 10 = 20.
Discussion:
17 comments Page 2 of 2.
Shravan Sharma said:
9 years ago
The correct answer is 19.
10 times from 30 to 39 and rest 9 from 3, 13, 23, 43, 53, 63, 73, 83, 93.
10 times from 30 to 39 and rest 9 from 3, 13, 23, 43, 53, 63, 73, 83, 93.
ALMOJEED said:
9 years ago
It's wrong, because 33 was counted twice. Therefore, the answer is 19.
Paulwin Jerome said:
1 decade ago
3, 13, 23, 33, 43, 53, 63, 73, 83, 93 = Eleven 3's.
30, 31, 32, 34, 35, 36, 37, 38, 39 = Nine 3's.
Therefor 11 + 9 = 20.
30, 31, 32, 34, 35, 36, 37, 38, 39 = Nine 3's.
Therefor 11 + 9 = 20.
Sundar said:
1 decade ago
@All
The correct answer is 20.
03, 13, 23, 43, 53, 63, 73, 83, 93 = 9 3s are there
30, 31, 32, 34, 35, 36, 37, 38, 39 = 9 3s are there
33 = 2 3s are there
Total = 9 + 9 + 2 = 20.
The correct answer is 20.
03, 13, 23, 43, 53, 63, 73, 83, 93 = 9 3s are there
30, 31, 32, 34, 35, 36, 37, 38, 39 = 9 3s are there
33 = 2 3s are there
Total = 9 + 9 + 2 = 20.
Ashish said:
1 decade ago
Yes the answer should be 19.
Senthilkumar said:
1 decade ago
NO the answer was 20 because in 33 we wrote down 3 in two times so 20 is the right answer but here they mistakenly said 33 two times
Mounika said:
1 decade ago
Here 4m 1 to 10 , we clearly have
10 no's:3,13,23,33,43,53,63,73,83,93
and more 9 no's:30,31,32,34,35,36,37,38,39
Since we have calculated 33 already need not count here .
Hence answer is 19.
10 no's:3,13,23,33,43,53,63,73,83,93
and more 9 no's:30,31,32,34,35,36,37,38,39
Since we have calculated 33 already need not count here .
Hence answer is 19.
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