Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 24)
24.
If you write down all the numbers from 1 to 100, then how many times do you write 3 ?
Answer: Option
Explanation:
Clearly, from 1 to 100, there are ten numbers with 3 as the unit's digit- 3, 13, 23, 33, 43, 53, 63, 73, 83, 93; and ten numbers with 3 as the ten's digit - 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.
So, required number = 10 + 10 = 20.
Discussion:
17 comments Page 1 of 2.
Ryan DCosta said:
2 years ago
According to me, the correct answer is 19 and not 20. You cannot account for 33 twice.
(10)
Pankaj said:
7 years ago
20 because 33 has 2 3's.
(2)
Siyad said:
8 years ago
@Mounika @Ashish @Almojeed @Shravan Sharma @Lokesh Sanam.
The answer is Option [C]. 20.
In 33, we have to write 3 twice.
Hope you will understand.
The answer is Option [C]. 20.
In 33, we have to write 3 twice.
Hope you will understand.
Neeraja said:
5 years ago
Thanks @Sundar.
Digvijay said:
7 years ago
@Sundar you're right.
In 33 we write 3 two times.
In 33 we write 3 two times.
Nisha Pawar said:
7 years ago
The Right answer is 20. I agree.
Himanshu Kumar Tiwari said:
7 years ago
The Right answer is 19.
Vishwajeet said:
8 years ago
33 is counted double.
Answer should be 19.
Answer should be 19.
Mark john ureta said:
8 years ago
Treat 3 as ones digit different to 3 use as a tens digit.
Mounika said:
1 decade ago
Here 4m 1 to 10 , we clearly have
10 no's:3,13,23,33,43,53,63,73,83,93
and more 9 no's:30,31,32,34,35,36,37,38,39
Since we have calculated 33 already need not count here .
Hence answer is 19.
10 no's:3,13,23,33,43,53,63,73,83,93
and more 9 no's:30,31,32,34,35,36,37,38,39
Since we have calculated 33 already need not count here .
Hence answer is 19.
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