Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 24)
24.
Two shafts 'A' and 'B' have the same material. The shaft 'A' is solid of diameter 100 mm. The shaft 'B' is hollow with outer diameter 100 mm and inner diameter 50 mm. The torque transmitted by shaft 'B' is __________ as that of shaft 'A'.
Discussion:
12 comments Page 1 of 2.
Anand Singh said:
1 decade ago
Anyone solve this?
Joel said:
10 years ago
Torque transmitted by a solid shaft: (pie)/16*(tau)*D^3.
(Here D is given 100).
Torque transmitted by a hollow shaft: (pie)/16*(tau)*((D^4 - d^4))/D.
(Here D = outer diameter = 100; d = inner diameter = 50).
Solve the above and you will get 15/16.
(Here D is given 100).
Torque transmitted by a hollow shaft: (pie)/16*(tau)*((D^4 - d^4))/D.
(Here D = outer diameter = 100; d = inner diameter = 50).
Solve the above and you will get 15/16.
(1)
Anand said:
8 years ago
Good explanation. Thanks.
Ankush said:
7 years ago
Strength of shaft depends upon the section modulus of shaft i.e. π/16 d^3.
Put the values of dia and compare the results.
Put the values of dia and compare the results.
Avtar said:
7 years ago
Answer should be 16/15.
(1)
Saurav said:
7 years ago
The correct Answer is 16/15.
(1)
Pratiksha said:
7 years ago
What is the value of tau?
Varma said:
6 years ago
16/15 is the correct one.
(3)
Krishna said:
5 years ago
Here, we can put d = D/2 in formula.
Jitendra kumar yadav said:
5 years ago
The right answer is 16/15.
(1)
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