Mechanical Engineering - Hydraulic Machines - Discussion

Discussion Forum : Hydraulic Machines - Section 1 (Q.No. 7)
7.
A Pelton wheel develops 1750 kW under a head of 100 metres while running at 200 r.p.m. and discharging 2500 litres of water per second. The unit power of the wheel is
0.25 kW
0.75 kW
1.75 kW
3.75 kW
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

PRATIK said:   1 decade ago
Unit power is the the power required to raise the fluid up to 1m head.

So,

Unit power = total power / total head.

= 175/100.

= 1.75.

Kapil said:   1 decade ago
Unit power= P/[H^(3/2)].

= 1750*10^3/100^(3/2).

= 1750 W.
= 1.75 KW.
(1)

MAK said:   8 years ago
You are right @Kapil.

Vish said:   8 years ago
I agree with you @Kapil.

Vijay solanki said:   8 years ago
I agree with you @Pratik.

I.P.Dwivedi said:   7 years ago
Unit power = P/[H^(3/2)].

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

Piyush said:   7 years ago
Unit power = p/h^(3/2),

So, we get 1.75 KW.

Lokesh said:   7 years ago
I agree with the explanation. Thank you all.

Nandlal yadav said:   7 years ago
I agree, thanks @Pratik.

MADHU said:   7 years ago
Thank you @KAPIL.


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