Mechanical Engineering - Hydraulic Machines - Discussion

7. 

A Pelton wheel develops 1750 kW under a head of 100 metres while running at 200 r.p.m. and discharging 2500 litres of water per second. The unit power of the wheel is

[A]. 0.25 kW
[B]. 0.75 kW
[C]. 1.75 kW
[D]. 3.75 kW

Answer: Option C

Explanation:

No answer description available for this question.

Pratik said: (Oct 6, 2013)  
Unit power is the the power required to raise the fluid up to 1m head.

So,

Unit power = total power / total head.

= 175/100.

= 1.75.

Kapil said: (Oct 21, 2013)  
Unit power= P/[H^(3/2)].

= 1750*10^3/100^(3/2).

= 1750 W.
= 1.75 KW.

Mak said: (Jul 7, 2016)  
You are right @Kapil.

Vish said: (Jul 29, 2016)  
I agree with you @Kapil.

Vijay Solanki said: (Aug 20, 2016)  
I agree with you @Pratik.

I.P.Dwivedi said: (Sep 7, 2016)  
Unit power = P/[H^(3/2)].

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

Piyush said: (Sep 29, 2016)  
Unit power = p/h^(3/2),

So, we get 1.75 KW.

Lokesh said: (Dec 11, 2016)  
I agree with the explanation. Thank you all.

Nandlal Yadav said: (Jul 20, 2017)  
I agree, thanks @Pratik.

Madhu said: (Jul 23, 2017)  
Thank you @KAPIL.

Sattibabu said: (Jan 7, 2018)  
Thank you for the explanation.

Rajendra said: (Jan 31, 2018)  
Unit power of Pelton wheel = P/H^3/2 so 1750/100^3/2=1.75KW.

Dharmesh Patel said: (Feb 1, 2018)  
Unit power is power by water can raise head for 1 meter.

Then,
We can apply the formula to find the Unit power as below:

Unit Power = p/H^3/2.
=1750*1000/100^3,
=1750000/1000000,
=1750 W,
=1.75 KW.

Krupal said: (May 2, 2019)  
I agree, thanks @Kapil.

Dev said: (Jun 7, 2019)  
Thanks all of you.

Sousend said: (Jun 9, 2019)  
Unit power= (Outpur power/H^(3/2)).

Hence 1750/1000=1.75.

Vishal said: (Oct 21, 2019)  
Unit power = P/[H^(3/2)].

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

Vihan said: (May 15, 2020)  
Agree @Kapil.

George Mwenya said: (Oct 10, 2020)  
Thanks all for explaining.

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