Mechanical Engineering - Hydraulic Machines - Discussion

Discussion Forum : Hydraulic Machines - Section 1 (Q.No. 7)
7.
A Pelton wheel develops 1750 kW under a head of 100 metres while running at 200 r.p.m. and discharging 2500 litres of water per second. The unit power of the wheel is
0.25 kW
0.75 kW
1.75 kW
3.75 kW
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Kapil said:   1 decade ago
Unit power= P/[H^(3/2)].

= 1750*10^3/100^(3/2).

= 1750 W.
= 1.75 KW.
(1)

Sousend said:   5 years ago
Unit power= (Outpur power/H^(3/2)).

Hence 1750/1000=1.75.
(1)

George Mwenya said:   3 years ago
Thanks all for explaining.

PRATIK said:   1 decade ago
Unit power is the the power required to raise the fluid up to 1m head.

So,

Unit power = total power / total head.

= 175/100.

= 1.75.

Vihan said:   4 years ago
Agree @Kapil.

Vishal said:   4 years ago
Unit power = P/[H^(3/2)].

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

Dev said:   5 years ago
Thanks all of you.

Krupal said:   5 years ago
I agree, thanks @Kapil.

Dharmesh Patel said:   6 years ago
Unit power is power by water can raise head for 1 meter.

Then,
We can apply the formula to find the Unit power as below:

Unit Power = p/H^3/2.
=1750*1000/100^3,
=1750000/1000000,
=1750 W,
=1.75 KW.

Rajendra said:   6 years ago
Unit power of Pelton wheel = P/H^3/2 so 1750/100^3/2=1.75KW.


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