# Mechanical Engineering - Hydraulic Machines - Discussion

Discussion Forum : Hydraulic Machines - Section 1 (Q.No. 7)

7.

A Pelton wheel develops 1750 kW under a head of 100 metres while running at 200 r.p.m. and discharging 2500 litres of water per second. The unit power of the wheel is

Discussion:

19 comments Page 1 of 2.
Dharmesh Patel said:
6 years ago

Unit power is power by water can raise head for 1 meter.

Then,

We can apply the formula to find the Unit power as below:

Unit Power = p/H^3/2.

=1750*1000/100^3,

=1750000/1000000,

=1750 W,

=1.75 KW.

Then,

We can apply the formula to find the Unit power as below:

Unit Power = p/H^3/2.

=1750*1000/100^3,

=1750000/1000000,

=1750 W,

=1.75 KW.

PRATIK said:
1 decade ago

Unit power is the the power required to raise the fluid up to 1m head.

So,

Unit power = total power / total head.

= 175/100.

= 1.75.

So,

Unit power = total power / total head.

= 175/100.

= 1.75.

Vishal said:
4 years ago

Unit power = P/[H^(3/2)].

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

I.P.Dwivedi said:
7 years ago

Unit power = P/[H^(3/2)].

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

Kapil said:
1 decade ago

Unit power= P/[H^(3/2)].

= 1750*10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

= 1750*10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

(1)

Rajendra said:
6 years ago

Unit power of Pelton wheel = P/H^3/2 so 1750/100^3/2=1.75KW.

Sousend said:
5 years ago

Unit power= (Outpur power/H^(3/2)).

Hence 1750/1000=1.75.

Hence 1750/1000=1.75.

(1)

Piyush said:
7 years ago

Unit power = p/h^(3/2),

So, we get 1.75 KW.

So, we get 1.75 KW.

Lokesh said:
7 years ago

I agree with the explanation. Thank you all.

Sattibabu said:
6 years ago

Thank you for the explanation.

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