# Mechanical Engineering - Hydraulic Machines - Discussion

Discussion Forum : Hydraulic Machines - Section 1 (Q.No. 7)
7.
A Pelton wheel develops 1750 kW under a head of 100 metres while running at 200 r.p.m. and discharging 2500 litres of water per second. The unit power of the wheel is
0.25 kW
0.75 kW
1.75 kW
3.75 kW
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 2 of 2.

Nandlal yadav said:   7 years ago
I agree, thanks @Pratik.

Lokesh said:   7 years ago
I agree with the explanation. Thank you all.

Piyush said:   7 years ago
Unit power = p/h^(3/2),

So, we get 1.75 KW.

I.P.Dwivedi said:   7 years ago
Unit power = P/[H^(3/2)].

= 1750 * 10^3/100^(3/2).

= 1750 W.

= 1.75 KW.

Vijay solanki said:   8 years ago
I agree with you @Pratik.

Vish said:   8 years ago
I agree with you @Kapil.

MAK said:   8 years ago
You are right @Kapil.

Unit power= P/[H^(3/2)].

= 1750*10^3/100^(3/2).

= 1750 W.
= 1.75 KW.
(1)

Unit power is the the power required to raise the fluid up to 1m head.

So,

Unit power = total power / total head.

= 175/100.

= 1.75.