Mechanical Engineering - Hydraulic Machines - Discussion
Discussion Forum : Hydraulic Machines - Section 1 (Q.No. 7)
7.
A Pelton wheel develops 1750 kW under a head of 100 metres while running at 200 r.p.m. and discharging 2500 litres of water per second. The unit power of the wheel is
Discussion:
19 comments Page 2 of 2.
Sattibabu said:
8 years ago
Thank you for the explanation.
Rajendra said:
8 years ago
Unit power of Pelton wheel = P/H^3/2 so 1750/100^3/2=1.75KW.
Dharmesh Patel said:
8 years ago
Unit power is power by water can raise head for 1 meter.
Then,
We can apply the formula to find the Unit power as below:
Unit Power = p/H^3/2.
=1750*1000/100^3,
=1750000/1000000,
=1750 W,
=1.75 KW.
Then,
We can apply the formula to find the Unit power as below:
Unit Power = p/H^3/2.
=1750*1000/100^3,
=1750000/1000000,
=1750 W,
=1.75 KW.
Krupal said:
6 years ago
I agree, thanks @Kapil.
Dev said:
6 years ago
Thanks all of you.
Sousend said:
6 years ago
Unit power= (Outpur power/H^(3/2)).
Hence 1750/1000=1.75.
Hence 1750/1000=1.75.
(2)
Vishal said:
6 years ago
Unit power = P/[H^(3/2)].
= 1750 * 10^3/100^(3/2).
= 1750 W.
= 1.75 KW.
= 1750 * 10^3/100^(3/2).
= 1750 W.
= 1.75 KW.
Vihan said:
5 years ago
Agree @Kapil.
George Mwenya said:
5 years ago
Thanks all for explaining.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers