General Knowledge - Chemistry - Discussion

Discussion Forum : Chemistry - Section 1 (Q.No. 56)
56.
The number of g-molecule of oxygen in 6.02 x 1024CO molecules is
1 gram of molecule
0.5 gram of molecule
5 gram of molecule
10 gram of molecule
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 1 of 3.

Kirtijain said:   1 decade ago
Please explain.

Swapnil Sontakke said:   1 decade ago
1gm of oxy contains 6.023x10^23 no. of moles. therefore 6.023x10^24 no. of moles will be in 10gm of oxy molecule. the ans should be option D.

Erkebulan from Astana said:   1 decade ago
Swapnil Sontakke cool answear.

Akash Biswas said:   1 decade ago
Its 5g molecule because 1g of CO molecule has 6.022*10^23 molecule of CO. Therefore 6.022*10^24 molecules has 10g of CO molecule. Hence out of 10g 5g is for only C.

Siya said:   1 decade ago
What @Swapnil sontakke said is right. only 1 gm of O2 has 6.022*10^23 molecules.

Therefore 6.023x10^24 no.of moles will be in 10 gm of O2 molecule.

Since in CO only 1 atom of Oxygen is present the answer is C.

Clint said:   1 decade ago
It should be letter D.

Whatever the formula of a certain substance, a mole of it will always contain 6.022x10^23 molecules. Thus, 6.02x10^24 molecules of any substance contains 10 moles of it, whether it is CO2, CO, or even DNA.

Gattu said:   1 decade ago
Is at correct g-molecule means gas molecule? then the answer is C. Otherwise the answer should be D.

Khan said:   1 decade ago
Answer C is correct because C+0.5 O2 = CO.

No. of g mole of CO = (6.02x10^24)/(6.02x10^23) = 10 g mole.

Therefore g-mole of O2 = 10x0.5 = 5.

Kalaiselvan.s said:   1 decade ago
I think 6.023*10^23+10^1 we can consider 6.023*10^23 = 1.

So 10^1 = 10.

CO = 12+16 = 28.
O = 16.

28/16 = 1.75.
10/1.75 = ~2.

Therefore 10/2 = 5.

Sanjeev choudhary said:   1 decade ago
Answer will D b/c 6.023*10^24/6.023*10^23=10.


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