General Knowledge - Chemistry - Discussion

Discussion Forum : Chemistry - Section 1 (Q.No. 56)
56.
The number of g-molecule of oxygen in 6.02 x 1024CO molecules is
1 gram of molecule
0.5 gram of molecule
5 gram of molecule
10 gram of molecule
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 1 of 3.

Sudip Bose said:   1 decade ago
1 CO molecule contains 1 O-atom.

1 mole CO equivalent to 6.02x10^23 molecules of CO contain 6.02x10^23 atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen.

Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2 molecule.

Note: 6.02x10^23 atoms = 1 gm-atom.

Vijay said:   9 years ago
Actually, my dear friends thank you very much for giving such wonderful answers.

But I have a doubt on a mole, 1mole = 6.023*10^23 molecules, then 2moles means double the 1 mole i.e.12.046 * 10^46 molecules, then for 10 moles = 60.23 * 10^230.

I am getting this one, how did you get 6.023 * 10^24?
(1)

Ghost rider said:   1 decade ago
5 gram is correct because number of gram-molecules means number of moles of O2 molecules. Now 6.02 x 10^24 CO molecules = 10 moles of CO (divided by 6.02 x 10^23) 1 mole of CO has 16 g or 0.5 mole of O2.

Therefore 10 moles of CO will give 10 x 0.5 = 5 moles or gram-molecules of O2 (oxygen).

Clint said:   1 decade ago
It should be letter D.

Whatever the formula of a certain substance, a mole of it will always contain 6.022x10^23 molecules. Thus, 6.02x10^24 molecules of any substance contains 10 moles of it, whether it is CO2, CO, or even DNA.

Irine said:   6 years ago
2C + O2 = 2CO.
2mol of CO = 1 mol of O2,
2 * 6.02 * 10^23 molecules of CO= 1g molecule of O2( bcs 1 mol = 6.02 * 10^23 molecules)
6.02 * 10^24 molecules of CO= ?
= 6.02 * 10^24/ 2,
= 6.02 *10^23.
= 10/2= 5 g molecules of O2.

Siya said:   1 decade ago
What @Swapnil sontakke said is right. only 1 gm of O2 has 6.022*10^23 molecules.

Therefore 6.023x10^24 no.of moles will be in 10 gm of O2 molecule.

Since in CO only 1 atom of Oxygen is present the answer is C.

Anshika said:   7 years ago
C is the correct answer.

CO has 16g O. i.e. half the amount of O2 (32g).

Now. Moles will be 6.022 * 10^24 * 1/2 ÷ 6.022 * 10^23.

i.e. equal to 5 moles (gm molecule).

Akash Biswas said:   1 decade ago
Its 5g molecule because 1g of CO molecule has 6.022*10^23 molecule of CO. Therefore 6.022*10^24 molecules has 10g of CO molecule. Hence out of 10g 5g is for only C.

Kalaiselvan.s said:   1 decade ago
I think 6.023*10^23+10^1 we can consider 6.023*10^23 = 1.

So 10^1 = 10.

CO = 12+16 = 28.
O = 16.

28/16 = 1.75.
10/1.75 = ~2.

Therefore 10/2 = 5.

Khan said:   1 decade ago
Answer C is correct because C+0.5 O2 = CO.

No. of g mole of CO = (6.02x10^24)/(6.02x10^23) = 10 g mole.

Therefore g-mole of O2 = 10x0.5 = 5.


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