General Knowledge - Chemistry - Discussion

Discussion Forum : Chemistry - Section 1 (Q.No. 56)
56.
The number of g-molecule of oxygen in 6.02 x 1024CO molecules is
1 gram of molecule
0.5 gram of molecule
5 gram of molecule
10 gram of molecule
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 1 of 3.

Irine said:   6 years ago
2C + O2 = 2CO.
2mol of CO = 1 mol of O2,
2 * 6.02 * 10^23 molecules of CO= 1g molecule of O2( bcs 1 mol = 6.02 * 10^23 molecules)
6.02 * 10^24 molecules of CO= ?
= 6.02 * 10^24/ 2,
= 6.02 *10^23.
= 10/2= 5 g molecules of O2.

Usman said:   7 years ago
When we have one gram then why we need mole?

Anshika said:   7 years ago
C is the correct answer.

CO has 16g O. i.e. half the amount of O2 (32g).

Now. Moles will be 6.022 * 10^24 * 1/2 ÷ 6.022 * 10^23.

i.e. equal to 5 moles (gm molecule).

Rahul said:   8 years ago
Can anyone explain me this question properly? Please!

Tushar Verma said:   8 years ago
Option C is the absolutely perfect answer. I agree.

Umme zainab said:   9 years ago
Option C is perfectly correct answer.

Vijay said:   9 years ago
Yes, 100% c is correct.

@Ghost Rider, you had given a very nice explanation.

Vijay said:   9 years ago
Actually, my dear friends thank you very much for giving such wonderful answers.

But I have a doubt on a mole, 1mole = 6.023*10^23 molecules, then 2moles means double the 1 mole i.e.12.046 * 10^46 molecules, then for 10 moles = 60.23 * 10^230.

I am getting this one, how did you get 6.023 * 10^24?
(1)

Sri said:   9 years ago
Can anyone explain me properly?

Isha said:   9 years ago
10 gram of molecule is the correct answer.
(1)


Post your comments here:

Your comments will be displayed after verification.