Engineering Mechanics - General Principles - Discussion

Discussion Forum : General Principles - General Questions (Q.No. 2)
2.

Using the basic trigonomic functions, determine the length of side AB of the right triangle.
h = 7.07
h = 10
h = 5
h = 14.14
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
35 comments Page 3 of 4.

Raja said:   1 decade ago
@Manju's method is easy.

Marghoobul Islam said:   1 decade ago
H/B=SIN 45*.

=>AB/AC= SIN 45*.

=>AB/10=0.707106781.

=>AB=0.707106781*10.

=>AB=7.07.

SUDHAKAR said:   1 decade ago
In Given Triangle by using trignomtric relations
sin (theta)= AB/AC=AB/10
we know that sin45=0.707
0.707=AB/10
=>AB=0.707*10

Kabaru said:   1 decade ago
SOH-CAH-TOA.

SIN(THETA) = OPPOSITE/HYPOTENUSE.
COS(THETA) = ADJACENT/HYPOTENUSE.

TAN(THETA) = OPPOSITE/ADJACENT.

THEREFORE AB = CAH.
AB = COS (THETA) = adj/hyp.
AB = COS 45 = ADJ/10.
AB = 10. COS45.

And, COS45 = 0.707,
AB = 10 . 0.707
AB = 7.07.

ASHUTOSH said:   1 decade ago
sin(45) = AB/10.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.

Mani said:   1 decade ago
Sin 45 = AB/10.
0.707*10 = AB.
AB = 7.07.

Anisha said:   1 decade ago
How to calculate hypotenuse of a right triangle?

Darshan Deore said:   1 decade ago
Sin45 = AB/10.
0 = AB/10.
AB = 7.07.

Sunil mlaviya said:   1 decade ago
sin 45 = ab/10.
(sin 45 = 0.07)

ab = .07x10.

ab = 7.07.

VENKATESHWARAN said:   1 decade ago
Without calculator how will you find out sin 45 is 0.707. Did you use any tricks?


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