Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.

Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 3 of 4.
Raja said:
1 decade ago
@Manju's method is easy.
Marghoobul Islam said:
1 decade ago
H/B=SIN 45*.
=>AB/AC= SIN 45*.
=>AB/10=0.707106781.
=>AB=0.707106781*10.
=>AB=7.07.
=>AB/AC= SIN 45*.
=>AB/10=0.707106781.
=>AB=0.707106781*10.
=>AB=7.07.
SUDHAKAR said:
1 decade ago
In Given Triangle by using trignomtric relations
sin (theta)= AB/AC=AB/10
we know that sin45=0.707
0.707=AB/10
=>AB=0.707*10
sin (theta)= AB/AC=AB/10
we know that sin45=0.707
0.707=AB/10
=>AB=0.707*10
Kabaru said:
1 decade ago
SOH-CAH-TOA.
SIN(THETA) = OPPOSITE/HYPOTENUSE.
COS(THETA) = ADJACENT/HYPOTENUSE.
TAN(THETA) = OPPOSITE/ADJACENT.
THEREFORE AB = CAH.
AB = COS (THETA) = adj/hyp.
AB = COS 45 = ADJ/10.
AB = 10. COS45.
And, COS45 = 0.707,
AB = 10 . 0.707
AB = 7.07.
SIN(THETA) = OPPOSITE/HYPOTENUSE.
COS(THETA) = ADJACENT/HYPOTENUSE.
TAN(THETA) = OPPOSITE/ADJACENT.
THEREFORE AB = CAH.
AB = COS (THETA) = adj/hyp.
AB = COS 45 = ADJ/10.
AB = 10. COS45.
And, COS45 = 0.707,
AB = 10 . 0.707
AB = 7.07.
ASHUTOSH said:
1 decade ago
sin(45) = AB/10.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.
Mani said:
1 decade ago
Sin 45 = AB/10.
0.707*10 = AB.
AB = 7.07.
0.707*10 = AB.
AB = 7.07.
Anisha said:
1 decade ago
How to calculate hypotenuse of a right triangle?
Darshan Deore said:
1 decade ago
Sin45 = AB/10.
0 = AB/10.
AB = 7.07.
0 = AB/10.
AB = 7.07.
Sunil mlaviya said:
1 decade ago
sin 45 = ab/10.
(sin 45 = 0.07)
ab = .07x10.
ab = 7.07.
(sin 45 = 0.07)
ab = .07x10.
ab = 7.07.
VENKATESHWARAN said:
1 decade ago
Without calculator how will you find out sin 45 is 0.707. Did you use any tricks?
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