Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 1 of 4.
Anisha said:
1 decade ago
How to calculate hypotenuse of a right triangle?
Daulu Reve said:
1 decade ago
sin45=AB/AC
sin45=AB/10
AB=sin45*10
AB=7.07
sin45=AB/10
AB=sin45*10
AB=7.07
Nikhil said:
1 decade ago
@Vishal method is easy.
Raja said:
1 decade ago
@Manju's method is easy.
Marghoobul Islam said:
1 decade ago
H/B=SIN 45*.
=>AB/AC= SIN 45*.
=>AB/10=0.707106781.
=>AB=0.707106781*10.
=>AB=7.07.
=>AB/AC= SIN 45*.
=>AB/10=0.707106781.
=>AB=0.707106781*10.
=>AB=7.07.
SUDHAKAR said:
1 decade ago
In Given Triangle by using trignomtric relations
sin (theta)= AB/AC=AB/10
we know that sin45=0.707
0.707=AB/10
=>AB=0.707*10
sin (theta)= AB/AC=AB/10
we know that sin45=0.707
0.707=AB/10
=>AB=0.707*10
Kabaru said:
1 decade ago
SOH-CAH-TOA.
SIN(THETA) = OPPOSITE/HYPOTENUSE.
COS(THETA) = ADJACENT/HYPOTENUSE.
TAN(THETA) = OPPOSITE/ADJACENT.
THEREFORE AB = CAH.
AB = COS (THETA) = adj/hyp.
AB = COS 45 = ADJ/10.
AB = 10. COS45.
And, COS45 = 0.707,
AB = 10 . 0.707
AB = 7.07.
SIN(THETA) = OPPOSITE/HYPOTENUSE.
COS(THETA) = ADJACENT/HYPOTENUSE.
TAN(THETA) = OPPOSITE/ADJACENT.
THEREFORE AB = CAH.
AB = COS (THETA) = adj/hyp.
AB = COS 45 = ADJ/10.
AB = 10. COS45.
And, COS45 = 0.707,
AB = 10 . 0.707
AB = 7.07.
ASHUTOSH said:
1 decade ago
sin(45) = AB/10.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.
Mani said:
1 decade ago
Sin 45 = AB/10.
0.707*10 = AB.
AB = 7.07.
0.707*10 = AB.
AB = 7.07.
Prakash said:
1 decade ago
sin theta=opp. side/hyp.
sin45=AB/10
.707=AB/10
AB=.707*10
AB=7.07
sin45=AB/10
.707=AB/10
AB=.707*10
AB=7.07
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