Engineering Mechanics - General Principles - Discussion

Discussion :: General Principles - General Questions (Q.No.2)

2. 


Using the basic trigonomic functions, determine the length of side AB of the right triangle.

[A]. h = 7.07
[B]. h = 10
[C]. h = 5
[D]. h = 14.14

Answer: Option A

Explanation:

No answer description available for this question.

Rathod Vishal said: (Nov 23, 2010)  
sin45=AB/10
.707=AB/10
AB=7.07

Nagaraju said: (Nov 24, 2010)  
Sin45 value = 1/1.414 = 0.707213579

Lokesh said: (Nov 27, 2010)  
hyp^2=opp^2+adj^2

10^2=x^+x^2(opp=adj=x,isosceles triangle)

height(h)=x=7.07

Prem said: (Dec 16, 2010)  
Sin 45 = AB/AC
so, AB = AC x Sin45
AB = 10 x Sin 45
AB = 7.07

Raji said: (Jan 4, 2011)  
From the given diagram, let AB=BC=x and AC=d
x^2 + x^2 = d^2
2(x^2) =d^2
on Substituting the value of d=10
2(x^2) = 100
x^2 = 50
= 2x25
x = 5 x [(2)^(1/2)]
= 5 x 1.141
= 7.07

Yramakrishna said: (Feb 21, 2011)  
sin45=AB/10
AB=7.07

Ramji said: (Mar 16, 2011)  
sin45 = 0.70
0.70*10 = 7.07

Ashwini said: (Mar 16, 2011)  
Let base and height= x (becoz angle is 45)

So x2+X2= 2X2=100

HENCE X=7.07

Madan said: (Apr 22, 2011)  
Sin45=ab/ac
where ac=10
then ab=sin45*ac
ab=.707*10
ab=7.07

Jai Praksh Singh said: (Jun 3, 2011)  
Sin 45 = AB/AC =AB/10
AB = .0707X10 = 7.07
AB=7.07

G.Kavipandi said: (Jul 26, 2011)  
AB=sin45*10
=7.07

G.Kavipandi said: (Jul 26, 2011)  
AB=sin theta * x .it direct formula to find distance in em

Ashok said: (Aug 22, 2011)  
AB=BC*AC
AB=SIN45*10
=0.707*10
AB=7.07

Manju G said: (Sep 13, 2011)  
Its very to find out,
Sin 45 = opp/ hy
opp = sin 45 x hy
= 1/sq.root of 2 x 10
opp = 7.07

Ajit Banne Bec Bagalkot said: (Oct 31, 2011)  
AB = ACsin45
AB = 10*0.707
AB = 7.07

Saharsh said: (Jan 17, 2012)  
Perpendicular AB
sin(45)= ---------------- = ------
hypotenuse 10

So,

AB = sin(45)x 10 = 0.707x10 = 7.07 Ans.

Bepo said: (Jan 23, 2012)  
sin 45=AB/AC
1/2^2=AB/10
10* 1/1.4142=AB/10
10* 0.707=AB
7.07=AB

Prakash said: (Jan 28, 2012)  
sin theta=opp. side/hyp.
sin45=AB/10
.707=AB/10
AB=.707*10
AB=7.07

Daulu Reve said: (Feb 10, 2012)  
sin45=AB/AC
sin45=AB/10
AB=sin45*10
AB=7.07

Nikhil said: (Feb 15, 2012)  
@Vishal method is easy.

Raja said: (May 23, 2012)  
@Manju's method is easy.

Marghoobul Islam said: (Jun 15, 2012)  
H/B=SIN 45*.

=>AB/AC= SIN 45*.

=>AB/10=0.707106781.

=>AB=0.707106781*10.

=>AB=7.07.

Sudhakar said: (Aug 30, 2012)  
In Given Triangle by using trignomtric relations
sin (theta)= AB/AC=AB/10
we know that sin45=0.707
0.707=AB/10
=>AB=0.707*10

Kabaru said: (Jan 19, 2014)  
SOH-CAH-TOA.

SIN(THETA) = OPPOSITE/HYPOTENUSE.
COS(THETA) = ADJACENT/HYPOTENUSE.

TAN(THETA) = OPPOSITE/ADJACENT.

THEREFORE AB = CAH.
AB = COS (THETA) = adj/hyp.
AB = COS 45 = ADJ/10.
AB = 10. COS45.

And, COS45 = 0.707,
AB = 10 . 0.707
AB = 7.07.

Ashutosh said: (Feb 2, 2014)  
sin(45) = AB/10.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.

Mani said: (Mar 10, 2014)  
Sin 45 = AB/10.
0.707*10 = AB.
AB = 7.07.

Anisha said: (May 18, 2014)  
How to calculate hypotenuse of a right triangle?

Darshan Deore said: (Oct 5, 2014)  
Sin45 = AB/10.
0 = AB/10.
AB = 7.07.

Sunil Mlaviya said: (Oct 22, 2014)  
sin 45 = ab/10.
(sin 45 = 0.07)

ab = .07x10.

ab = 7.07.

Venkateshwaran said: (Apr 6, 2015)  
Without calculator how will you find out sin 45 is 0.707. Did you use any tricks?

Nitika Arora said: (Sep 28, 2015)  
AB = Perpendicular; AC = hypotenuse.

Now we know sin 45 = AB/AC.

->> 1/sqrt2 = AB/10.

->> 0.707 = AB/10 (1/sqrt2 = 0.707).

->> AB = 10*0.707.

->> AB = 7.07.

Md.Aminurrahman said: (Jul 16, 2016)  
Sine45 degree = AB\10.
AB = 7.07 => Answer.

Sanket Kamble Pce said: (Feb 13, 2017)  
Sin 45 = AB/10.
0.707 * 10 = AB.
AB = 7.07.

Ravikumar said: (Jun 13, 2017)  
Sin θ =opposite side/hypotenuse sin(theera) = AB/ AC.
AB=Ac sin45. = 10 sin45= 10 * 0.707.

So, AB = 7.07.

Janardhana said: (Jul 29, 2017)  
You are correct @Ashwini.

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