Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 4 of 4.
Raji said:
1 decade ago
From the given diagram, let AB=BC=x and AC=d
x^2 + x^2 = d^2
2(x^2) =d^2
on Substituting the value of d=10
2(x^2) = 100
x^2 = 50
= 2x25
x = 5 x [(2)^(1/2)]
= 5 x 1.141
= 7.07
x^2 + x^2 = d^2
2(x^2) =d^2
on Substituting the value of d=10
2(x^2) = 100
x^2 = 50
= 2x25
x = 5 x [(2)^(1/2)]
= 5 x 1.141
= 7.07
Prem said:
1 decade ago
Sin 45 = AB/AC
so, AB = AC x Sin45
AB = 10 x Sin 45
AB = 7.07
so, AB = AC x Sin45
AB = 10 x Sin 45
AB = 7.07
Lokesh said:
1 decade ago
hyp^2=opp^2+adj^2
10^2=x^+x^2(opp=adj=x,isosceles triangle)
height(h)=x=7.07
10^2=x^+x^2(opp=adj=x,isosceles triangle)
height(h)=x=7.07
Nagaraju said:
1 decade ago
Sin45 value = 1/1.414 = 0.707213579
RATHOD VISHAL said:
1 decade ago
sin45=AB/10
.707=AB/10
AB=7.07
.707=AB/10
AB=7.07
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