Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 3 of 4.
AJIT BANNE BEC BAGALKOT said:
1 decade ago
AB = ACsin45
AB = 10*0.707
AB = 7.07
AB = 10*0.707
AB = 7.07
Manju G said:
1 decade ago
Its very to find out,
Sin 45 = opp/ hy
opp = sin 45 x hy
= 1/sq.root of 2 x 10
opp = 7.07
Sin 45 = opp/ hy
opp = sin 45 x hy
= 1/sq.root of 2 x 10
opp = 7.07
ASHOK said:
1 decade ago
AB=BC*AC
AB=SIN45*10
=0.707*10
AB=7.07
AB=SIN45*10
=0.707*10
AB=7.07
G.kavipandi said:
1 decade ago
AB=sin theta * x .it direct formula to find distance in em
G.kavipandi said:
1 decade ago
AB=sin45*10
=7.07
=7.07
Jai Praksh Singh said:
1 decade ago
Sin 45 = AB/AC =AB/10
AB = .0707X10 = 7.07
AB=7.07
AB = .0707X10 = 7.07
AB=7.07
Madan said:
1 decade ago
Sin45=ab/ac
where ac=10
then ab=sin45*ac
ab=.707*10
ab=7.07
where ac=10
then ab=sin45*ac
ab=.707*10
ab=7.07
ASHWINI said:
1 decade ago
Let base and height= x (becoz angle is 45)
So x2+X2= 2X2=100
HENCE X=7.07
So x2+X2= 2X2=100
HENCE X=7.07
Ramji said:
1 decade ago
sin45 = 0.70
0.70*10 = 7.07
0.70*10 = 7.07
Yramakrishna said:
1 decade ago
sin45=AB/10
AB=7.07
AB=7.07
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