Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 4 of 4.
Nitika arora said:
10 years ago
AB = Perpendicular; AC = hypotenuse.
Now we know sin 45 = AB/AC.
->> 1/sqrt2 = AB/10.
->> 0.707 = AB/10 (1/sqrt2 = 0.707).
->> AB = 10*0.707.
->> AB = 7.07.
Now we know sin 45 = AB/AC.
->> 1/sqrt2 = AB/10.
->> 0.707 = AB/10 (1/sqrt2 = 0.707).
->> AB = 10*0.707.
->> AB = 7.07.
Md.AminurRahman said:
9 years ago
Sine45 degree = AB\10.
AB = 7.07 => Answer.
AB = 7.07 => Answer.
Sanket kamble pce said:
9 years ago
Sin 45 = AB/10.
0.707 * 10 = AB.
AB = 7.07.
0.707 * 10 = AB.
AB = 7.07.
Ravikumar said:
8 years ago
Sin θ =opposite side/hypotenuse sin(theera) = AB/ AC.
AB=Ac sin45. = 10 sin45= 10 * 0.707.
So, AB = 7.07.
AB=Ac sin45. = 10 sin45= 10 * 0.707.
So, AB = 7.07.
Janardhana said:
8 years ago
You are correct @Ashwini.
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