Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 2 of 4.
G.kavipandi said:
1 decade ago
AB=sin45*10
=7.07
=7.07
G.kavipandi said:
1 decade ago
AB=sin theta * x .it direct formula to find distance in em
ASHOK said:
1 decade ago
AB=BC*AC
AB=SIN45*10
=0.707*10
AB=7.07
AB=SIN45*10
=0.707*10
AB=7.07
Manju G said:
1 decade ago
Its very to find out,
Sin 45 = opp/ hy
opp = sin 45 x hy
= 1/sq.root of 2 x 10
opp = 7.07
Sin 45 = opp/ hy
opp = sin 45 x hy
= 1/sq.root of 2 x 10
opp = 7.07
AJIT BANNE BEC BAGALKOT said:
1 decade ago
AB = ACsin45
AB = 10*0.707
AB = 7.07
AB = 10*0.707
AB = 7.07
Saharsh said:
1 decade ago
Perpendicular AB
sin(45)= ---------------- = ------
hypotenuse 10
So,
AB = sin(45)x 10 = 0.707x10 = 7.07 Ans.
sin(45)= ---------------- = ------
hypotenuse 10
So,
AB = sin(45)x 10 = 0.707x10 = 7.07 Ans.
BEPO said:
1 decade ago
sin 45=AB/AC
1/2^2=AB/10
10* 1/1.4142=AB/10
10* 0.707=AB
7.07=AB
1/2^2=AB/10
10* 1/1.4142=AB/10
10* 0.707=AB
7.07=AB
Prakash said:
1 decade ago
sin theta=opp. side/hyp.
sin45=AB/10
.707=AB/10
AB=.707*10
AB=7.07
sin45=AB/10
.707=AB/10
AB=.707*10
AB=7.07
Daulu Reve said:
1 decade ago
sin45=AB/AC
sin45=AB/10
AB=sin45*10
AB=7.07
sin45=AB/10
AB=sin45*10
AB=7.07
Nikhil said:
1 decade ago
@Vishal method is easy.
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