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Electronics and Communication Engineering - Exam Questions Papers

Exercise : Exam Questions Papers - Exam Paper 5
41.
In a JK flip-flop, J is connected to Q and K is connected to Q outputs. The JK FF converts into a
RS FF
D FF
T FF
Clocked RS FF
Answer: Option
Explanation:

Both the input is opposit to each other hence it is D FF.

42.
A point charge of 6 μC is located at the origin, uniform line charge density of 180 nC/m of 8 m length lies along the x axis and a uniform sheet of charge equal to 25 nC/m2 of area p x 42 lies in the z = 0 plane. Calculate total electric flux leaving the surface of sphere of 4 m radius centered at origin.
86.97 μC
8.697 nC
8.697 μC
86.97 nC
Answer: Option
Explanation:

According to Gauss's law total flux leaving the closed surface is equal to the charge enclosed by the closed surface

Qencl = (6 x 10-6) + (8 x 180 x 10-6) + (p x 42 x 25 x 10-9)

= (6 x 10-6) + (1.44 x 10-6) + (1.257 x 10-6)

= 8.697 μ Coulombs.

43.
An infinite ladder is constructed with 1 Ω and 2 Ω resistors as shown below. Find i
8.1818 A
0 A
9 A
cannot be determined
Answer: Option
Explanation:

As ladder is infinite

∴

2R + R2 = 2 + 3R

R2 - R - 2 = 0

∴

R = 2 or R = -1

Negative value of R is not possible

∴ R = 2

∴

i = 9 A.

44.
Consider the matrix The value of ep is
Answer: Option
Explanation:

find L-1[sI -A]-1

find inverse Laplace transform of the expression.

45.
Find current flowing through 1 H inductor at t = 0, at which switch 'S' is opened.
0
2
3
5
Answer: Option
Explanation:

For t = 0+ current in L is

circuit at t = 0+

∴ I is Io = 3 A.

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