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Electronics and Communication Engineering - Exam Questions Papers

Exercise : Exam Questions Papers - Exam Paper 5
31.
The probability density function (PDF) of a random variable X is as shown below

The corresponding cumulative distribution function (CDF) has the form
Answer: Option
Explanation:

Cumulative distribution function (Pdf) dx

Then when we integrate the line from (-1, 0) to (0, 1) we get a parabolic curve.

The maximum value of Pdf can be 1.

32.
The system with given pole-zero diagram is __________
Causal
Anti-causal
Both sided
Cannot be determined
Answer: Option
Explanation:

Z transform for the pole zero plot will be

Degree of numerator > degree of denominator. Also ROC is not defined.

Hence response of the system cannot be determined.

33.
For the waveform shown below, the slew rate and full power bandwidth with respect to op-amp will be respectively
0.02 V/μsec, 1.59 KHz
0.04 V/μsec, 1.59 KHz
0.02 V/μsec, 3.58 KHz
0.02 V/μsec, 1.59 KHz
Answer: Option
Explanation:

Full power bandwidth

34.
In the derivation of expression for peak percent overshoot, , Which one the following conditions is NOT required?
System is linear and time invariant
The system transfer function has a pair of complex conjugate poles and no zeros.
There is no transportation delay in the system.
The system has zero initial conditions.
Answer: Option
Explanation:

.

35.
The impulse response h(t) of a linear invariant continuous time system is given by h(t) = exp (- 2t) u(t), where u(t) denotes the unit step function. The output of this system to the sinusoidal input x(t) = 2cos(2t) for all time t, is
0
2-0.25 cos (2t - 0.125p)
2-0.5 cos (2t - 0.125p)
2-0.5 cos (2t - 0.25p)
Answer: Option
Explanation:

When input is sinusoidal then output is also sinusoidal with same frequency but amplitude and phase changes. Thus amplitude is

Phase is tan-1 = 0.25 p

Thus y(t) = 2-0.5 cos(2t - 0.25p).

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