Electronics and Communication Engineering - Exam Questions Papers

Replacing current and voltage by their phasors I and 10e^jp/b, resp. and by jω = j1000, we obtain the phasor equation

I + 10^-3(j1000I) = 10e^jp/6

or I(1 + j1) = 10e^jp/6

Having determined the value of I, we now find the required solution to be

I(t) = R_c [I e^jωt] = R_c[7.07e ^-jp/2 e^j1000t]

= 7.07 cos (1000t - 15°)A.

Use similar method. But for capacitor take inverse of value of capacitance and then apply procedure same as in resistance case. After getting the final answer take inverse of result to get C_eq

∴

In Cuboid case,

For resistance

For inductance

For capacitance.

RMS value .