Electronics and Communication Engineering - Exam Questions Papers
Exercise : Exam Questions Papers - Exam Paper 3
- Exam Questions Papers - Exam Paper 12
- Exam Questions Papers - Exam Paper 22
- Exam Questions Papers - Exam Paper 21
- Exam Questions Papers - Exam Paper 20
- Exam Questions Papers - Exam Paper 19
- Exam Questions Papers - Exam Paper 18
- Exam Questions Papers - Exam Paper 17
- Exam Questions Papers - Exam Paper 16
- Exam Questions Papers - Exam Paper 15
- Exam Questions Papers - Exam Paper 14
- Exam Questions Papers - Exam Paper 13
- Exam Questions Papers - Exam Paper 1
- Exam Questions Papers - Exam Paper 11
- Exam Questions Papers - Exam Paper 10
- Exam Questions Papers - Exam Paper 9
- Exam Questions Papers - Exam Paper 8
- Exam Questions Papers - Exam Paper 7
- Exam Questions Papers - Exam Paper 6
- Exam Questions Papers - Exam Paper 5
- Exam Questions Papers - Exam Paper 4
- Exam Questions Papers - Exam Paper 3
- Exam Questions Papers - Exam Paper 2
6.
The maximum percent overshoot with maximum value of first overshoot as 3.5 V and steady state value as 2.575 V is
Answer: Option
Explanation:
From the transient response characteristics, Maximum percentage overshoot (MPO) is given as
MPO decides the relative stability of the system.
7.
Find Vo(t) for the following circuit.
Data: L = 1 H, C = 1 F, R1 = R2 = 1 Ω and zero initial conditions.

Data: L = 1 H, C = 1 F, R1 = R2 = 1 Ω and zero initial conditions.

Answer: Option
Explanation:
E(s) = L[e(t)] = L[5 sin 3t]
Let V1(s) = Voltage across L
and
V2(s) = Voltage across R2
V(s) = V1(s) - V2(s)
8.
An XOR gate with 8 variable is as follows:
A ⊕ B ⊕ C ⊕ D ⊕ E ⊕ F ⊕ G ⊕ H
The number of minterms in the Boolean expression is
A ⊕ B ⊕ C ⊕ D ⊕ E ⊕ F ⊕ G ⊕ H
The number of minterms in the Boolean expression is
Answer: Option
Explanation:
.
9.
The figure shown below is designed to act as a constant current source across the load resistor. The β of transistor is 50. What is the value of load current?


Answer: Option
Explanation:
Voltage at base = 12 - 5 = 7 v
Voltage at emitter = 7 + 0.7 = 7.7 v
Current through R1 = 2 mA
Thus current through load = = 1.96 mA.
10.
For a given magnetic material operating in linear mode B = 0.06 T. Assume permeability = 51, then magnetization is:
Answer: Option
Explanation:
μ = λmH,
λm = (μ - 1) = 51 - 1 = 50
μ = 50 x H 46834.
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers