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Electronics and Communication Engineering - Exam Questions Papers

Exercise : Exam Questions Papers - Exam Paper 1
16.
Find 'X' in the circuit below :

f1(A, B, C, D) = Σ(6, 7, 13, 14);
f2(A, B, C, D) = Σ(3, 6, 7);
f3(A, B, C, D) = Σ(5, 6, 7, 14, 15)
p(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 15)
0
Σ(14)
1
Answer: Option
Explanation:

f1(A, B, C, D) = ∑(6, 7, 13, 14)

f2(A, B, C, D) = ∑(3, 6, 7)

f1 ⊕ f2 = ∑(3, 13, 14)

f3 x (f1 ⊕ f2) = ∑(14) = y

X = f1 x y ⇒ ∑14.

17.
Suppose that the modulating signal is m(t) = 2cos (2pfmt) and the carrier signal is xC(t) = AC cos(2pfct), which one of the following is a conventional AM signal without over modulation?
x(t) = Acm(t)cos(2pfct)
x(t) = Ac [1 + m(t)]cos (2pfct)
x(t) = Accos(2pfmt)cos(2pfct) + Acsin(2pfmt)sin(2pfct)
Answer: Option
Explanation:

(C) is without over modulation.

18.
What are the values of Emax and Emin displayed on the oscilloscope, when a 1 kV P-P carries is modulated to 50%?
2 kV, 0.5 kV
1 kV, 0.5 kV
0.75 kV, 0.25 kV
0.5 kV, 1.5 kV
Answer: Option
Explanation:

Emax - Emin = 0.5 x 1 kV = 0.5 kV

2Emax = 1.5 kVi, Emax = 0.75 kV

Emin = 0.25 kV.

19.
Consider the common emitter amplifier shown below with the following circuit parameters: β = 100, gm = 0.3861 A/V, r0 = ∞ rp = 259 Ω, Rs = 1 kΩ, RB = 93 kΩ, RC = 250 Ω, RL = 1 kW, C1 = ∞ and C2 = 4.7mF.

The resistance seen by the source Vs is
258 Ω
1258 Ω
93 kΩ
∞
Answer: Option
Explanation:

Zs = Rs + (RB || Brs)

rc = 2.475 = 1.258 kV

20.
As the temperature increases the mobility of electrons __________ .
decreases because the number of carries increases with increased collisions
increases because the number of carries decreases with decreased collisions
remains same
none of the above
Answer: Option
Explanation:

Mobility of electrons

m = 2.5 for electrons and 2.7 for holes in Si.

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