Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 1 (Q.No. 19)
19.
Consider the common emitter amplifier shown below with the following circuit parameters: β = 100, gm = 0.3861 A/V, r0 = ∞ rp = 259 Ω, Rs = 1 kΩ, RB = 93 kΩ, RC = 250 Ω, RL = 1 kW, C1 = ∞ and C2 = 4.7mF.
The resistance seen by the source Vs is
The resistance seen by the source Vs is
Answer: Option
Explanation:
Zs = Rs + (RB || Brs)
rc = 2.475 = 1.258 kV
Discussion:
2 comments Page 1 of 1.
Vinay said:
9 years ago
Could you explain, please.
Gopal said:
9 years ago
Rpi = bita/gm = 100/0.3
so, rb/rpi = rc.
so, rb/rpi = rc.
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