Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 2 (Q.No. 5)
5.
Calculate the resistivity of n-type semiconductor from the following data, Density of holes = 5 x 1012 cm-3. Density of electrons = 8 x 1013 cm-3, mobility of conduction electron = 2.3 x 104 cm2/ V-sec and mobility of holes = 100 cm2/V-sec.
Answer: Option
Explanation:
Resistivity(r) = 
.
σ = e(neue + nnun).
Discussion:
13 comments Page 1 of 2.
Lik said:
6 years ago
Conductivity= 1.6x10^-19 * (5x10^12 * 100 + 8x10^13 * 2.3x10^4) = 0.29488.
Since this is in cm multiply it by 100 to get value in m which is 29.488,
Resistivity = 1/conductivity,
Resistivity = 0.034 ohm-meter.
Since this is in cm multiply it by 100 to get value in m which is 29.488,
Resistivity = 1/conductivity,
Resistivity = 0.034 ohm-meter.
(2)
Jidsa said:
6 years ago
@Psalmer Since cm is in the denominator before getting the reciprocal of it for the resistivity, you must multiply it by 100 to convert it to the meter.
(1)
Psalmer said:
6 years ago
@Lik When you want to convert the cm to meter, it must be divided by 100 and not multiply.
0.29488cm x (1m/100cm).
0.29488cm x (1m/100cm).
Himans said:
8 years ago
I think the correct answer is actually 0.034 ohm-metre
Siva said:
1 decade ago
Please tell me the step wise answer please.
Siddharth said:
7 years ago
Here e = 1.6*10^-19 and n represents holes.
Prachin said:
9 years ago
Anyone, please explain the calculate.
Varun said:
1 decade ago
Anyone please-step wise explain.
Naresh said:
7 years ago
Please explain the solution.
Sandhiya said:
8 years ago
Explain step wise, please.
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