Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion

Discussion Forum : Electronic Devices and Circuits - Section 2 (Q.No. 5)
5.
Calculate the resistivity of n-type semiconductor from the following data, Density of holes = 5 x 1012 cm-3. Density of electrons = 8 x 1013 cm-3, mobility of conduction electron = 2.3 x 104 cm2/ V-sec and mobility of holes = 100 cm2/V-sec.
0.43 Ω-m
0.34 Ω-m
0.42 Ω-m
0.24 Ω-m
Answer: Option
Explanation:

Resistivity(r) = .

σ = e(neue + nnun).

Discussion:
13 comments Page 1 of 2.

Jidsa said:   4 years ago
@Psalmer Since cm is in the denominator before getting the reciprocal of it for the resistivity, you must multiply it by 100 to convert it to the meter.
(1)

Psalmer said:   4 years ago
@Lik When you want to convert the cm to meter, it must be divided by 100 and not multiply.
0.29488cm x (1m/100cm).

Lyle said:   5 years ago
Thanks @Lik.

Lik said:   5 years ago
Conductivity= 1.6x10^-19 * (5x10^12 * 100 + 8x10^13 * 2.3x10^4) = 0.29488.
Since this is in cm multiply it by 100 to get value in m which is 29.488,
Resistivity = 1/conductivity,
Resistivity = 0.034 ohm-meter.
(1)

Siddharth said:   5 years ago
Here e = 1.6*10^-19 and n represents holes.

Keerthana said:   6 years ago
Please explain the answer.
(1)

Senthil said:   6 years ago
Please explain the answer.

Naresh said:   6 years ago
Please explain the solution.

Sandhiya said:   7 years ago
Explain step wise, please.

Himans said:   7 years ago
I think the correct answer is actually 0.034 ohm-metre


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