Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 2 (Q.No. 5)
5.
Calculate the resistivity of n-type semiconductor from the following data, Density of holes = 5 x 1012 cm-3. Density of electrons = 8 x 1013 cm-3, mobility of conduction electron = 2.3 x 104 cm2/ V-sec and mobility of holes = 100 cm2/V-sec.
Answer: Option
Explanation:
Resistivity(r) = 
.
σ = e(neue + nnun).
Discussion:
13 comments Page 1 of 2.
Varun said:
1 decade ago
Anyone please-step wise explain.
Siva said:
1 decade ago
Please tell me the step wise answer please.
Prachin said:
9 years ago
Anyone, please explain the calculate.
Himans said:
8 years ago
I think the correct answer is actually 0.034 ohm-metre
Sandhiya said:
8 years ago
Explain step wise, please.
Naresh said:
7 years ago
Please explain the solution.
Senthil said:
7 years ago
Please explain the answer.
Keerthana said:
7 years ago
Please explain the answer.
(1)
Siddharth said:
7 years ago
Here e = 1.6*10^-19 and n represents holes.
Lik said:
6 years ago
Conductivity= 1.6x10^-19 * (5x10^12 * 100 + 8x10^13 * 2.3x10^4) = 0.29488.
Since this is in cm multiply it by 100 to get value in m which is 29.488,
Resistivity = 1/conductivity,
Resistivity = 0.034 ohm-meter.
Since this is in cm multiply it by 100 to get value in m which is 29.488,
Resistivity = 1/conductivity,
Resistivity = 0.034 ohm-meter.
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers