Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 4 (Q.No. 25)
25.
The work function of a photo surface whose threshold wave length is 1200 A, will be
Discussion:
5 comments Page 1 of 1.
Komal said:
7 years ago
Answer would be (1.24/(1200*10-4))= 10.3ev.
Sandy said:
8 years ago
You are right @Hari Charan.
Hari charan said:
9 years ago
E(ev) = 12400/(wave length in Angstrom).
According to answer, the wavelength may be 12000 A° instead of 1200 A°.
According to answer, the wavelength may be 12000 A° instead of 1200 A°.
Dushyant Joshi said:
1 decade ago
1 A = 10^-10 METER.
Now solve,
E(ev) = 1.24/1200*10^-4.
Now solve,
E(ev) = 1.24/1200*10^-4.
Dushyant Joshi said:
1 decade ago
E(in ev) = 1.24/wavelength in Micrometer.
Here given unit of wavelength is wrong.
Here given unit of wavelength is wrong.
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