Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000 
100,000
200,000
1,000,000
Discussion:
32 comments Page 3 of 4.
Apoorva chourasiya said:
9 years ago
This is sensitivity concept.
Sensitivity = 2000ohm/volt.
Voltage = 5v
So, s = ohm/volt.
Ohm = s * volt.
Ohm = 2000 * 5,
Ohm = 10000ohm.
Sensitivity = 2000ohm/volt.
Voltage = 5v
So, s = ohm/volt.
Ohm = s * volt.
Ohm = 2000 * 5,
Ohm = 10000ohm.
Junaid said:
9 years ago
Not understanding. Please explain me to get it.
Deepak mohapatra said:
8 years ago
In 1volt resistance is 20000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
(1)
Din said:
8 years ago
Thanks for all your explanations.
Gaurav Rathor said:
8 years ago
Not understanding. Please explain me to get it.
YoungLove said:
8 years ago
Internal resistance is given by Sensivity (20,000) * scale deflection (5)
Which is 20,000 * 5 = 100,000 ohms
Which is 20,000 * 5 = 100,000 ohms
Jay chandra said:
8 years ago
Thank you @Nedunchezlien.
Swetha said:
7 years ago
Thank you all.
(1)
Rajendra said:
7 years ago
Thanks @Nedunchezhian.
Priyanshu said:
6 years ago
For voltmeter operation very low current needed, hence it contains internal resistance in series, hence 5 resistors will be added and we will get 100000.
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