Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000 
100,000
200,000
1,000,000
Discussion:
32 comments Page 1 of 4.
MD.SHAHINUR said:
3 years ago
Excellent explanation, thanks all.
(4)
M.Nedunchezhian said:
1 decade ago
The voltmeter have an internal resistance of 20,000 ohm/volt.
That is for 1 volt the resistance is 20,000 ohm.
Therefore,for 5 volt the resistance is = 5*20,000=1,00,000 ohm.
That is for 1 volt the resistance is 20,000 ohm.
Therefore,for 5 volt the resistance is = 5*20,000=1,00,000 ohm.
(1)
Kamal Yadav said:
5 years ago
According to voltmeter sensitivity(ohm/volt),
S=total voltmeter res./ full scale reading=Rm/Vfs.
or, Rm = S*Vfs = 20000*5 = 100,000 ohm.
S=total voltmeter res./ full scale reading=Rm/Vfs.
or, Rm = S*Vfs = 20000*5 = 100,000 ohm.
(1)
Swetha said:
7 years ago
Thank you all.
(1)
Deepak mohapatra said:
8 years ago
In 1volt resistance is 20000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
(1)
Om prakash said:
9 years ago
Very good @Juilee.
Sagar Kalekar said:
10 years ago
I = 1/(Ifsd).
Ifsd = Full scale deflection i.e. Sensitivity of the meter.
I = 1/20000 = 0.5 x 10^-4.
R = V/I.
R = 5/0.5 x 10^-4.
R = 100, 000 ohm.
Ifsd = Full scale deflection i.e. Sensitivity of the meter.
I = 1/20000 = 0.5 x 10^-4.
R = V/I.
R = 5/0.5 x 10^-4.
R = 100, 000 ohm.
Sanjay Meena said:
9 years ago
Om's I = V/R rule formula apply.
Nilesh Gitte said:
9 years ago
Correct explanation @M.Nedunchezhian.
Apoorva chourasiya said:
9 years ago
This is sensitivity concept.
Sensitivity = 2000ohm/volt.
Voltage = 5v
So, s = ohm/volt.
Ohm = s * volt.
Ohm = 2000 * 5,
Ohm = 10000ohm.
Sensitivity = 2000ohm/volt.
Voltage = 5v
So, s = ohm/volt.
Ohm = s * volt.
Ohm = 2000 * 5,
Ohm = 10000ohm.
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