Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000 
100,000
200,000
1,000,000
Discussion:
32 comments Page 1 of 4.
MD.SHAHINUR said:
4 years ago
Excellent explanation, thanks all.
(4)
Kamal Yadav said:
6 years ago
According to voltmeter sensitivity(ohm/volt),
S=total voltmeter res./ full scale reading=Rm/Vfs.
or, Rm = S*Vfs = 20000*5 = 100,000 ohm.
S=total voltmeter res./ full scale reading=Rm/Vfs.
or, Rm = S*Vfs = 20000*5 = 100,000 ohm.
(2)
YoungLove said:
9 years ago
Internal resistance is given by Sensivity (20,000) * scale deflection (5)
Which is 20,000 * 5 = 100,000 ohms
Which is 20,000 * 5 = 100,000 ohms
(1)
Deepak mohapatra said:
10 years ago
In 1volt resistance is 20000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
(1)
Swetha said:
8 years ago
Thank you all.
(1)
M.Nedunchezhian said:
2 decades ago
The voltmeter have an internal resistance of 20,000 ohm/volt.
That is for 1 volt the resistance is 20,000 ohm.
Therefore,for 5 volt the resistance is = 5*20,000=1,00,000 ohm.
That is for 1 volt the resistance is 20,000 ohm.
Therefore,for 5 volt the resistance is = 5*20,000=1,00,000 ohm.
(1)
Rajendra said:
8 years ago
Thanks @Nedunchezhian.
Priyanshu said:
7 years ago
For voltmeter operation very low current needed, hence it contains internal resistance in series, hence 5 resistors will be added and we will get 100000.
Jay chandra said:
9 years ago
Thank you @Nedunchezlien.
Sagar Kalekar said:
1 decade ago
I = 1/(Ifsd).
Ifsd = Full scale deflection i.e. Sensitivity of the meter.
I = 1/20000 = 0.5 x 10^-4.
R = V/I.
R = 5/0.5 x 10^-4.
R = 100, 000 ohm.
Ifsd = Full scale deflection i.e. Sensitivity of the meter.
I = 1/20000 = 0.5 x 10^-4.
R = V/I.
R = 5/0.5 x 10^-4.
R = 100, 000 ohm.
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