Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000 
100,000
200,000
1,000,000
Discussion:
32 comments Page 2 of 4.
Junaid said:
9 years ago
Not understanding. Please explain me to get it.
Din said:
8 years ago
Thanks for all your explanations.
Gaurav Rathor said:
8 years ago
Not understanding. Please explain me to get it.
YoungLove said:
8 years ago
Internal resistance is given by Sensivity (20,000) * scale deflection (5)
Which is 20,000 * 5 = 100,000 ohms
Which is 20,000 * 5 = 100,000 ohms
Jay chandra said:
8 years ago
Thank you @Nedunchezlien.
Rajendra said:
7 years ago
Thanks @Nedunchezhian.
Priyanshu said:
6 years ago
For voltmeter operation very low current needed, hence it contains internal resistance in series, hence 5 resistors will be added and we will get 100000.
JUILEE MILIND GHATOLE said:
1 decade ago
Internal Resistance=20000ohm/V
Voltage=5v
I.R.*V=20000*5
=100,000ohm
Voltage=5v
I.R.*V=20000*5
=100,000ohm
Raji said:
1 decade ago
Don't think complicate manner just think about logic its simple the question is per volt it.
Consumes om 20000 there fore 5 volts just multiply it.
Consumes om 20000 there fore 5 volts just multiply it.
LALITHA said:
1 decade ago
Given,
r = 20,000 ohms per volt.
For 1v r = 20,000.
For 5v R = 20,000*5 = 100,000.
r = 20,000 ohms per volt.
For 1v r = 20,000.
For 5v R = 20,000*5 = 100,000.
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