Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000 
100,000
200,000
1,000,000
Discussion:
32 comments Page 2 of 4.
Gaurav Rathor said:
9 years ago
Not understanding. Please explain me to get it.
Din said:
10 years ago
Thanks for all your explanations.
Junaid said:
10 years ago
Not understanding. Please explain me to get it.
Apoorva chourasiya said:
10 years ago
This is sensitivity concept.
Sensitivity = 2000ohm/volt.
Voltage = 5v
So, s = ohm/volt.
Ohm = s * volt.
Ohm = 2000 * 5,
Ohm = 10000ohm.
Sensitivity = 2000ohm/volt.
Voltage = 5v
So, s = ohm/volt.
Ohm = s * volt.
Ohm = 2000 * 5,
Ohm = 10000ohm.
Nilesh Gitte said:
10 years ago
Correct explanation @M.Nedunchezhian.
Sanjay Meena said:
10 years ago
Om's I = V/R rule formula apply.
Om prakash said:
1 decade ago
Very good @Juilee.
JUILEE MILIND GHATOLE said:
2 decades ago
Internal Resistance=20000ohm/V
Voltage=5v
I.R.*V=20000*5
=100,000ohm
Voltage=5v
I.R.*V=20000*5
=100,000ohm
Raji said:
1 decade ago
Don't think complicate manner just think about logic its simple the question is per volt it.
Consumes om 20000 there fore 5 volts just multiply it.
Consumes om 20000 there fore 5 volts just multiply it.
LALITHA said:
1 decade ago
Given,
r = 20,000 ohms per volt.
For 1v r = 20,000.
For 5v R = 20,000*5 = 100,000.
r = 20,000 ohms per volt.
For 1v r = 20,000.
For 5v R = 20,000*5 = 100,000.
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