Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000
100,000
200,000
1,000,000
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
32 comments Page 1 of 4.

JUILEE said:   1 decade ago
According to me....
Internal resistance =20000ohm/v
voltage=5v
I.R.*V=20000*5
=100,000ohm

JUILEE MILIND GHATOLE said:   1 decade ago
Internal Resistance=20000ohm/V
Voltage=5v
I.R.*V=20000*5
=100,000ohm

M.Nedunchezhian said:   1 decade ago
The voltmeter have an internal resistance of 20,000 ohm/volt.
That is for 1 volt the resistance is 20,000 ohm.
Therefore,for 5 volt the resistance is = 5*20,000=1,00,000 ohm.
(1)

Harish said:   1 decade ago
Thank you Nadunchezhian.

Ganeshbabu said:   1 decade ago
Thank you Nedunchezlien.

Anand said:   1 decade ago
Nice explaination Juilee & Nedunchezlien

Arun Sankar said:   1 decade ago
Ms. Juilee,

I have some doubt,

For finding I means, I=v/R.

But why your using this formula here IR*v.

Can you explain?

Dinesh said:   1 decade ago
IR means Internal Resistance not current and resistance.

Ian Glenn said:   1 decade ago
We can use basic algebra here by ratio and proportion.

20000 ohm/volt means 20000 ohm per unit of volt.

Let x= internal resistance,

20000 ohm/volt=x/5volts.

So x = 20000*5 = 100,000ohm.

Jyo said:   1 decade ago
According to ohm's law,

IR = 20,000ohm/volt.

V = 5v.

IR*V = 20,000*5 = 100000.


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