Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000 
100,000
200,000
1,000,000
Discussion:
32 comments Page 2 of 4.
Ahmed babu said:
1 decade ago
The voltmeter have an internal resistance of 20,000 ohm/volt.
That is for 1 volt the resistance is 20,000 ohm.
Therefore, for 5 volt the resistance is = 5*20,000 = 1,00,000 ohm.
That is for 1 volt the resistance is 20,000 ohm.
Therefore, for 5 volt the resistance is = 5*20,000 = 1,00,000 ohm.
Sunil kumar said:
1 decade ago
For 1 volt internal resistance is 20000 ohms.
For 5 volt internal resistance is ? (X).
V is proportional to R hence 1/5 =20000/X.
Hence X=100000.
For 5 volt internal resistance is ? (X).
V is proportional to R hence 1/5 =20000/X.
Hence X=100000.
Nazim uddin said:
1 decade ago
The internal resistant 20000 for 1 volt that = v = 5 and ohm law,
R = v*I 5*20000 = 100,000 ohm.
R = v*I 5*20000 = 100,000 ohm.
ZERO said:
1 decade ago
Don't tell me that IR is internal resistance? base on the ohms law I= amperes R= resistance, and E= volts. IR=V? in the ohms law pyramid not this IR*V?
LALITHA said:
1 decade ago
Given,
r = 20,000 ohms per volt.
For 1v r = 20,000.
For 5v R = 20,000*5 = 100,000.
r = 20,000 ohms per volt.
For 1v r = 20,000.
For 5v R = 20,000*5 = 100,000.
Raji said:
1 decade ago
Don't think complicate manner just think about logic its simple the question is per volt it.
Consumes om 20000 there fore 5 volts just multiply it.
Consumes om 20000 there fore 5 volts just multiply it.
Sagar Kalekar said:
10 years ago
I = 1/(Ifsd).
Ifsd = Full scale deflection i.e. Sensitivity of the meter.
I = 1/20000 = 0.5 x 10^-4.
R = V/I.
R = 5/0.5 x 10^-4.
R = 100, 000 ohm.
Ifsd = Full scale deflection i.e. Sensitivity of the meter.
I = 1/20000 = 0.5 x 10^-4.
R = V/I.
R = 5/0.5 x 10^-4.
R = 100, 000 ohm.
Om prakash said:
9 years ago
Very good @Juilee.
Sanjay Meena said:
9 years ago
Om's I = V/R rule formula apply.
Nilesh Gitte said:
9 years ago
Correct explanation @M.Nedunchezhian.
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