Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000 
100,000
200,000
1,000,000
Discussion:
32 comments Page 1 of 4.
MD.SHAHINUR said:
2 years ago
Excellent explanation, thanks all.
(4)
Kamal Yadav said:
4 years ago
According to voltmeter sensitivity(ohm/volt),
S=total voltmeter res./ full scale reading=Rm/Vfs.
or, Rm = S*Vfs = 20000*5 = 100,000 ohm.
S=total voltmeter res./ full scale reading=Rm/Vfs.
or, Rm = S*Vfs = 20000*5 = 100,000 ohm.
(1)
Priyanshu said:
6 years ago
For voltmeter operation very low current needed, hence it contains internal resistance in series, hence 5 resistors will be added and we will get 100000.
Rajendra said:
6 years ago
Thanks @Nedunchezhian.
Swetha said:
7 years ago
Thank you all.
(1)
Jay chandra said:
7 years ago
Thank you @Nedunchezlien.
YoungLove said:
8 years ago
Internal resistance is given by Sensivity (20,000) * scale deflection (5)
Which is 20,000 * 5 = 100,000 ohms
Which is 20,000 * 5 = 100,000 ohms
Gaurav Rathor said:
8 years ago
Not understanding. Please explain me to get it.
Din said:
8 years ago
Thanks for all your explanations.
Deepak mohapatra said:
8 years ago
In 1volt resistance is 20000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
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