Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 8)
8.
What is the approximate resistance setting of a rheostat in which 650 mA of current flows with a 150 V source?
9.7
97
23
230
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
23 comments Page 1 of 3.

Ghulam mohy ud din said:   4 years ago
1000ma = 1A,

When we convert mili amper into amper then 1000 uses the small unit to large unit like;
650/1000 = 0.65 amper.

NIHAL P NAVAS said:   1 decade ago
V = IR.
R = V/I.

Given I = 650 mA = (650 x 10^3) = 0.65 A.

V = 150 V.

Therefore R = 150/0.65 = 230.77~~ 230 ohms.
(1)

PARMINDER SINGH said:   1 decade ago
I=V/R
I=650ma
V=150
R=?
650ma=150/R
650a/1000=150/R
65a/100=150/R
R*65a/100=150
R=150*100/65
R=15000/65
R=230

Adane said:   3 years ago
Given I= 650 mA =0.65Amp.
V= 150 V.

req = R?
Solution R = V/I = 150v/0.65Amp = 230.769.
(5)

Shyam patiala said:   1 decade ago
V=150V
I=650mA I=650/1000A
R=?

V=IR
R=V/I

R=150*1000/650
R=150000/650
R=15000/65
R=230ohm

SUNIL said:   9 years ago
V =150, I = 650 mA, R = ?,

I = 650 mA = 650/1000 = 0.65,

R = V/I = 150/0.65 = 230 Ω.

Veenashri said:   9 years ago
V = 150.
I = 650.

=> V/I = 150/650 = 0.230777.

=> R = 0.23077/1000.

=> 230 OHM.
(1)

Khenz santos said:   1 decade ago
V = IR.
R = V/I.
I = 650 mA.
V = 150 V.

So, R = 150/(650*10^-3).

R = 230 ohms.

Prasanth said:   7 years ago
150v.
650ma.
R=?.

R = v/I.
=150/(0.65),
I= 650/1000 = 0.65,
150/0.65 = 230.

Matthew sandoval said:   6 years ago
where did the 100 come from? I understand the 1000 not the 100 though.
(1)


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