Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 8)
8.
What is the approximate resistance setting of a rheostat in which 650 mA of current flows with a 150 V source?
9.7 
97
23
230
Discussion:
23 comments Page 1 of 3.
Adane said:
3 years ago
Given I= 650 mA =0.65Amp.
V= 150 V.
req = R?
Solution R = V/I = 150v/0.65Amp = 230.769.
V= 150 V.
req = R?
Solution R = V/I = 150v/0.65Amp = 230.769.
(5)
JohnLerr Espenoza said:
2 years ago
R = I÷V.
R = 650÷150.
= 230 Ohms.
R = 650÷150.
= 230 Ohms.
(1)
Matthew sandoval said:
6 years ago
where did the 100 come from? I understand the 1000 not the 100 though.
(1)
NIHAL P NAVAS said:
1 decade ago
V = IR.
R = V/I.
Given I = 650 mA = (650 x 10^3) = 0.65 A.
V = 150 V.
Therefore R = 150/0.65 = 230.77~~ 230 ohms.
R = V/I.
Given I = 650 mA = (650 x 10^3) = 0.65 A.
V = 150 V.
Therefore R = 150/0.65 = 230.77~~ 230 ohms.
(1)
Veenashri said:
9 years ago
V = 150.
I = 650.
=> V/I = 150/650 = 0.230777.
=> R = 0.23077/1000.
=> 230 OHM.
I = 650.
=> V/I = 150/650 = 0.230777.
=> R = 0.23077/1000.
=> 230 OHM.
(1)
Pork said:
10 years ago
Where did you get that 1000?
Ghulam mohy ud din said:
4 years ago
1000ma = 1A,
When we convert mili amper into amper then 1000 uses the small unit to large unit like;
650/1000 = 0.65 amper.
When we convert mili amper into amper then 1000 uses the small unit to large unit like;
650/1000 = 0.65 amper.
Piyush Mishra said:
5 years ago
I=V/R
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
Subhash said:
7 years ago
650*(10^-3) = 650 * (1/10^3).
So =650/1000.
So =650/1000.
Anil said:
7 years ago
How come 1000 here?
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