Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 8)
8.
What is the approximate resistance setting of a rheostat in which 650 mA of current flows with a 150 V source?
9.7 
97
23
230
Discussion:
23 comments Page 2 of 3.
Prasanth said:
7 years ago
150v.
650ma.
R=?.
R = v/I.
=150/(0.65),
I= 650/1000 = 0.65,
150/0.65 = 230.
650ma.
R=?.
R = v/I.
=150/(0.65),
I= 650/1000 = 0.65,
150/0.65 = 230.
Sarabjit Singh said:
8 years ago
Very nice explanations. Thank you all.
SUNIL said:
9 years ago
V =150, I = 650 mA, R = ?,
I = 650 mA = 650/1000 = 0.65,
R = V/I = 150/0.65 = 230 Ω.
I = 650 mA = 650/1000 = 0.65,
R = V/I = 150/0.65 = 230 Ω.
PARMINDER SINGH said:
1 decade ago
I=V/R
I=650ma
V=150
R=?
650ma=150/R
650a/1000=150/R
65a/100=150/R
R*65a/100=150
R=150*100/65
R=15000/65
R=230
I=650ma
V=150
R=?
650ma=150/R
650a/1000=150/R
65a/100=150/R
R*65a/100=150
R=150*100/65
R=15000/65
R=230
Pork said:
10 years ago
Where did you get that 1000?
Khenz santos said:
1 decade ago
V = IR.
R = V/I.
I = 650 mA.
V = 150 V.
So, R = 150/(650*10^-3).
R = 230 ohms.
R = V/I.
I = 650 mA.
V = 150 V.
So, R = 150/(650*10^-3).
R = 230 ohms.
Manoj said:
1 decade ago
v = 150v.
i = 150/650/1000 = 0.65.
150*0.65 = 230 v.
i = 150/650/1000 = 0.65.
150*0.65 = 230 v.
Suresh Kumar Rangaraj said:
1 decade ago
v = 150v.
i = 650*10^-3.
r = v/i.
r = 150/(650*10^-3) .
r = 230.
i = 650*10^-3.
r = v/i.
r = 150/(650*10^-3) .
r = 230.
Ramkumar said:
1 decade ago
v=150v
i=650ma=650*10^-3
v=ir
r=v/i
=150/650810^-3
=230ohm
i=650ma=650*10^-3
v=ir
r=v/i
=150/650810^-3
=230ohm
Shyam patiala said:
1 decade ago
V=150V
I=650mA I=650/1000A
R=?
V=IR
R=V/I
R=150*1000/650
R=150000/650
R=15000/65
R=230ohm
I=650mA I=650/1000A
R=?
V=IR
R=V/I
R=150*1000/650
R=150000/650
R=15000/65
R=230ohm
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