Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 8)
8.
What is the approximate resistance setting of a rheostat in which 650 mA of current flows with a 150 V source?
9.7 
97
23
230
Discussion:
23 comments Page 1 of 3.
JohnLerr Espenoza said:
2 years ago
R = I÷V.
R = 650÷150.
= 230 Ohms.
R = 650÷150.
= 230 Ohms.
(1)
Adane said:
3 years ago
Given I= 650 mA =0.65Amp.
V= 150 V.
req = R?
Solution R = V/I = 150v/0.65Amp = 230.769.
V= 150 V.
req = R?
Solution R = V/I = 150v/0.65Amp = 230.769.
(5)
Ghulam mohy ud din said:
4 years ago
1000ma = 1A,
When we convert mili amper into amper then 1000 uses the small unit to large unit like;
650/1000 = 0.65 amper.
When we convert mili amper into amper then 1000 uses the small unit to large unit like;
650/1000 = 0.65 amper.
Piyush Mishra said:
5 years ago
I=V/R
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
Matthew sandoval said:
6 years ago
where did the 100 come from? I understand the 1000 not the 100 though.
(1)
Subhash said:
7 years ago
650*(10^-3) = 650 * (1/10^3).
So =650/1000.
So =650/1000.
Anil said:
7 years ago
How come 1000 here?
Prasanth said:
7 years ago
150v.
650ma.
R=?.
R = v/I.
=150/(0.65),
I= 650/1000 = 0.65,
150/0.65 = 230.
650ma.
R=?.
R = v/I.
=150/(0.65),
I= 650/1000 = 0.65,
150/0.65 = 230.
Sarabjit Singh said:
8 years ago
Very nice explanations. Thank you all.
SUNIL said:
9 years ago
V =150, I = 650 mA, R = ?,
I = 650 mA = 650/1000 = 0.65,
R = V/I = 150/0.65 = 230 Ω.
I = 650 mA = 650/1000 = 0.65,
R = V/I = 150/0.65 = 230 Ω.
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