Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 8)
8.
What is the approximate resistance setting of a rheostat in which 650 mA of current flows with a 150 V source?
9.7 
97
23
230
Discussion:
23 comments Page 1 of 3.
PARMINDER SINGH said:
1 decade ago
I=V/R
I=650ma
V=150
R=?
650ma=150/R
650a/1000=150/R
65a/100=150/R
R*65a/100=150
R=150*100/65
R=15000/65
R=230
I=650ma
V=150
R=?
650ma=150/R
650a/1000=150/R
65a/100=150/R
R*65a/100=150
R=150*100/65
R=15000/65
R=230
Anand said:
1 decade ago
Nice answer parminder
MURUGAPERUMAL said:
1 decade ago
V=IR
SO,R=150/650*10^-3,
R=150/.65,
R=230 OHMS.
SO,R=150/650*10^-3,
R=150/.65,
R=230 OHMS.
Prashant said:
1 decade ago
I=650mA,
I=650*10^3A,
V=150V,
R=V/I;
R=150/(650*10^3);
R=230 ohm
I=650*10^3A,
V=150V,
R=V/I;
R=150/(650*10^3);
R=230 ohm
Shyam patiala said:
1 decade ago
V=150V
I=650mA I=650/1000A
R=?
V=IR
R=V/I
R=150*1000/650
R=150000/650
R=15000/65
R=230ohm
I=650mA I=650/1000A
R=?
V=IR
R=V/I
R=150*1000/650
R=150000/650
R=15000/65
R=230ohm
Ramkumar said:
1 decade ago
v=150v
i=650ma=650*10^-3
v=ir
r=v/i
=150/650810^-3
=230ohm
i=650ma=650*10^-3
v=ir
r=v/i
=150/650810^-3
=230ohm
Suresh Kumar Rangaraj said:
1 decade ago
v = 150v.
i = 650*10^-3.
r = v/i.
r = 150/(650*10^-3) .
r = 230.
i = 650*10^-3.
r = v/i.
r = 150/(650*10^-3) .
r = 230.
Manoj said:
1 decade ago
v = 150v.
i = 150/650/1000 = 0.65.
150*0.65 = 230 v.
i = 150/650/1000 = 0.65.
150*0.65 = 230 v.
Khenz santos said:
1 decade ago
V = IR.
R = V/I.
I = 650 mA.
V = 150 V.
So, R = 150/(650*10^-3).
R = 230 ohms.
R = V/I.
I = 650 mA.
V = 150 V.
So, R = 150/(650*10^-3).
R = 230 ohms.
NIHAL P NAVAS said:
1 decade ago
V = IR.
R = V/I.
Given I = 650 mA = (650 x 10^3) = 0.65 A.
V = 150 V.
Therefore R = 150/0.65 = 230.77~~ 230 ohms.
R = V/I.
Given I = 650 mA = (650 x 10^3) = 0.65 A.
V = 150 V.
Therefore R = 150/0.65 = 230.77~~ 230 ohms.
(1)
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