Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 8)
8.
What is the approximate resistance setting of a rheostat in which 650 mA of current flows with a 150 V source?
9.7 
97
23
230
Discussion:
23 comments Page 2 of 3.
Pork said:
10 years ago
Where did you get that 1000?
Pork said:
10 years ago
Where did you get that 1000?
Veenashri said:
9 years ago
V = 150.
I = 650.
=> V/I = 150/650 = 0.230777.
=> R = 0.23077/1000.
=> 230 OHM.
I = 650.
=> V/I = 150/650 = 0.230777.
=> R = 0.23077/1000.
=> 230 OHM.
(1)
SUNIL said:
9 years ago
V =150, I = 650 mA, R = ?,
I = 650 mA = 650/1000 = 0.65,
R = V/I = 150/0.65 = 230 Ω.
I = 650 mA = 650/1000 = 0.65,
R = V/I = 150/0.65 = 230 Ω.
Sarabjit Singh said:
8 years ago
Very nice explanations. Thank you all.
Prasanth said:
7 years ago
150v.
650ma.
R=?.
R = v/I.
=150/(0.65),
I= 650/1000 = 0.65,
150/0.65 = 230.
650ma.
R=?.
R = v/I.
=150/(0.65),
I= 650/1000 = 0.65,
150/0.65 = 230.
Anil said:
7 years ago
How come 1000 here?
Subhash said:
7 years ago
650*(10^-3) = 650 * (1/10^3).
So =650/1000.
So =650/1000.
Matthew sandoval said:
6 years ago
where did the 100 come from? I understand the 1000 not the 100 though.
(1)
Piyush Mishra said:
5 years ago
I=V/R
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
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