Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 8)
8.
What is the approximate resistance setting of a rheostat in which 650 mA of current flows with a 150 V source?
9.7 
97
23
230
Discussion:
23 comments Page 2 of 3.
Suresh Kumar Rangaraj said:
1 decade ago
v = 150v.
i = 650*10^-3.
r = v/i.
r = 150/(650*10^-3) .
r = 230.
i = 650*10^-3.
r = v/i.
r = 150/(650*10^-3) .
r = 230.
Prashant said:
1 decade ago
I=650mA,
I=650*10^3A,
V=150V,
R=V/I;
R=150/(650*10^3);
R=230 ohm
I=650*10^3A,
V=150V,
R=V/I;
R=150/(650*10^3);
R=230 ohm
Ramkumar said:
1 decade ago
v=150v
i=650ma=650*10^-3
v=ir
r=v/i
=150/650810^-3
=230ohm
i=650ma=650*10^-3
v=ir
r=v/i
=150/650810^-3
=230ohm
Piyush Mishra said:
5 years ago
I=V/R
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
i=150/R
R=V/I
R=150/0.650
R=230.736 => 230 Ohm.
Manoj said:
1 decade ago
v = 150v.
i = 150/650/1000 = 0.65.
150*0.65 = 230 v.
i = 150/650/1000 = 0.65.
150*0.65 = 230 v.
MURUGAPERUMAL said:
1 decade ago
V=IR
SO,R=150/650*10^-3,
R=150/.65,
R=230 OHMS.
SO,R=150/650*10^-3,
R=150/.65,
R=230 OHMS.
Subhash said:
7 years ago
650*(10^-3) = 650 * (1/10^3).
So =650/1000.
So =650/1000.
Sarabjit Singh said:
8 years ago
Very nice explanations. Thank you all.
JohnLerr Espenoza said:
2 years ago
R = I÷V.
R = 650÷150.
= 230 Ohms.
R = 650÷150.
= 230 Ohms.
(1)
Pork said:
10 years ago
Where did you get that 1000?
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