Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 4)
4.
A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?
Discussion:
29 comments Page 1 of 3.
Raza said:
6 years ago
Total kWH = power * time.
= 350 (watt) *24 (hour) *24 (days),
= 201600 watt hour,
= 201.6 kWH.
= 350 (watt) *24 (hour) *24 (days),
= 201600 watt hour,
= 201.6 kWH.
(9)
Ali BaBa said:
6 years ago
Thanks to all for explaining the answer.
(5)
Tapas Khan said:
3 years ago
Kilowatt/Hour Means = ( 350 * 24 * 24)/1000.
= 201.6kwh.
= 201.6kwh.
(4)
Md Kaium said:
4 years ago
KWh= (350*24*24)/1000
=201.6kwh.
=201.6kwh.
(2)
Pramod shinva said:
1 decade ago
1 day = 24 hours.
24 days = 576 hours.
KW H = P*TIME IN HOURS.
= 350*576 (We are used here 350 watts not a kw).
= 201600. Watt hours.
= 201600/1000.
= 201.6 KW H. IS ANSWER.
24 days = 576 hours.
KW H = P*TIME IN HOURS.
= 350*576 (We are used here 350 watts not a kw).
= 201600. Watt hours.
= 201600/1000.
= 201.6 KW H. IS ANSWER.
(2)
Rathi said:
1 decade ago
@Radha.
Because 1kW = 1000 W. So 201600 Watt hours is equal to 201.6 kWh.
Because 1kW = 1000 W. So 201600 Watt hours is equal to 201.6 kWh.
Pravin gaikwad said:
6 years ago
Here, it is (use in watt * total hours)/1000.
Sstyam said:
7 years ago
You are correct, Thanks @Gopi.
Mahantesh said:
7 years ago
201.6kwh is correct.
ABHI said:
8 years ago
P=9*120=1080WATT....... FOR UNITY pf.
FOR 20 MIN,
E=(1080*20)/1000 =21.6kwh.
FOR 20 MIN,
E=(1080*20)/1000 =21.6kwh.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers