Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 4)
4.
A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?
Discussion:
29 comments Page 2 of 3.
Padma said:
8 years ago
Yes, you both are correct @Gopi and @Rajesh.
Sham said:
9 years ago
Thank you @Pramod Shinva.
Mukeshbhai ramanbhai ganvit said:
9 years ago
An electrical iron drawing 9 A from 120 V Supply main is operated for 20 minutes, the energy consumed is?
CHAVITINA RAMAKRISHNA said:
9 years ago
@Messuli.
In the 'KILO watt-hour' asked, that is why we divided with 1000 in the calculation.
In the 'KILO watt-hour' asked, that is why we divided with 1000 in the calculation.
Messuli said:
9 years ago
Help please, where do we obtain 1000 from.
Noor Nawaz said:
1 decade ago
350*24 days*24 hours/1000 for conversion into kilos.
Gopi said:
1 decade ago
Kwh = (350*24*24)/1000
= 201.6kWh
= 201.6kWh
Radha said:
1 decade ago
Hello how you have taken 1000? why you divided ?
Tshering said:
1 decade ago
Energy(kWh)= Power(kW) x Time(hrs)
Power=350 watt i.e 350/1000= 0.350 kW
Time(hr)= 24days, i.e 24x24= 576 hrs
Therefore,
E= 576x0.350= 201.6
hence energy consumed = 201.6 kWh
Power=350 watt i.e 350/1000= 0.350 kW
Time(hr)= 24days, i.e 24x24= 576 hrs
Therefore,
E= 576x0.350= 201.6
hence energy consumed = 201.6 kWh
N KIRAN said:
1 decade ago
350w*24days*24hours = 201.6kw all are says correct answer.
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